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3 years ago

Not sure about this one help please

Mathematics

1 answer:

lutik1710 [3]3 years ago

5 0

Answer:

a) -1

Step-by-step explanation:

Slope is also known as the gradient

1. assign a value to x and solve for y:

when x = 2, y = 2

when x = 4, y = 0

2. Next, use the equation of a straight line to find the gradient

y = mx + c

y is the y-coordinate, m is the gradient, x is the x-coordinate, c is the point where the line crosses the y-axis, which is found by equating y to 0 and solving for x

so y = mx + c becomes 2 = m*2 + 4, which then becomes 2 = 2m + 4

2m = -2 (take 4 away from 2)

m = -1

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Complete the equation of the line through (6,-6) and (8,8)

melomori [17]

General formula to determine the equation of the line
y - y₁ = m(x - x₁)
(x₁,y₁) is one of the points which lies n the line
m represents the slope

Find the slope
Given:
(x₁,y₁) = (6,-6)
(x₂,y₂) = (8,8)

We could find the slope by using this formula
m = $\dfrac{ y_{2} -y_{1} }{ x_{2} -x_{1} }$

Plug in the numbers
m = $\dfrac{ y_{2} -y_{1} }{ x_{2} -x_{1} }$
m = $\dfrac{8-(-6)}{8-6}$
m = $\dfrac{14}{ 2 }$
m = 7
The slope is 7

Determine the line equation
Plug one of the points (you could choose any of points given from the question) and the slope to the formula of line equation
y - y₁ = m(x - x₁)
y - (-6) = 7(x - 6)
y + 6 = 7x - 42
y = 7x - 42 - 6
y = 7x - 48
This is the equation of the line

3 0

3 years ago

Please help me on this problem !

Rashid [163]

Answer:

x = 5 , y = 5 $\sqrt{3}$

Step-by-step explanation:

Using the sine and cosine ratios in the right triangle and exact values.

sin30° = $\frac{1}{2}$ , cos30° = $\frac{\sqrt{3} }{2}$ , then

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2x = 10 ( divide both sides by 2 )

x = 5

and

cos30° = $\frac{adjacent}{hypotenuse}$ = $\frac{y}{10}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

2y = 10 $\sqrt{3}$ ( divide both sides by 2 )

y = 5 $\sqrt{3}$

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Answer:

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my order my friend's order

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+ 10.29 + 0.59

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Lapatulllka [165]

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