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EleoNora [17]
3 years ago
11

a thermometer has its steam marked in millimetre instead of degree celsius. The lower fixed points is 180 mm calculate the tempe

rature in degrees Celsius thermometer reads 45mm
Physics
1 answer:
Nady [450]3 years ago
4 0

Answer:hi

Explanation:

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A less-dense liquid of density rho1 floats on top of a more-dense liquid of density rho2. A uniform cylinder of length l and den
Umnica [9.8K]

Answer:

Explanation:

Given

\rho=density\ of\ cylinder\\\rho_1=less\ dense\ cylinder\\\rho_2=more\ dense\ cylinder

Suppose V is the volume of a cylinder

Also L_1=length\ in\ less\ dense\ part\\L_2=length\ in\ dense\ part\\L=length\ of\ cylinder\\V=A\times L\\where\ A=area\ of\ cross-section\\

Now, we can write

The weight of the cylinder is supported by the buoyant forces of two liquids

\rho Vg=\rho_1 V_1g+\rho_2 V_2g\\\rho ALg=\rho_1 A\times L_1g+\rho_2 A\times L_2g\\\\\rho L=\rho_1 L_1+\rho_2 L_2\\Also, L=L_1+L_2

using the above equation we can write

L_2=\frac{\rho-\rho_1}{\rho_2-\rho_1}\cdot L\\\frac{L_2}{L}=\frac{\rho-\rho_1}{\rho_2-\rho_1}

5 0
3 years ago
Briefly explain why small-angle grain boundaries are not as effective in interfering with the slip process as are high-angle gra
artcher [175]

Answer:

Compared to High angle, relatively less presence of Crystallographic misalignment in grain boundary for small angle is reason behind its less effectiveness in interfering with slip process

Explanation:

Because of relatively much less presence of crystallographic misalignment in grain boundary for small angle, small grain boundaries are not as effective in compare to high angle in interfering with slip process

Less crystallographic misalignment in grain boundary causes not much change in slip direction and therefore interference to slip process is minimal.

8 0
3 years ago
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