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3 years ago

These graphs show measurements of the density of air as different sound waves pass a single point.

Physics

2 answers:

inessss [21]3 years ago

7 0

Answer: The graph with the highest density of air.

Explanation: The graphs are missing, but il try to explain this problem anyways.

Soundwaves are mechanical waves, that need a medium to move (commonly, the medium is the air)

As those mechanical waves affect the air, the density of air in some areas increase and in others decrease, and when that "wave of air" impacts a receptor, like your ear, you receive the information of the sound, like pitch and intensity.

As more air impacts the receptor, more "loud" is the noise, and as you may know, density = mass/volume, so as biggest is the density of air in a point, this means that we have more mass of air at that point, which is directly related to the intensity or loudness of the sound wave at that point

Ymorist [56]3 years ago

5 0

Answer: D!

It is the option with the greatest amplitude.

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Answer the following questions.<br><br> show your full steps please

aleksandr82 [10.1K]

Answer:

Explanation:

If we let our reference frame travel at 30 m/s with the constant speed car, The accelerating car increases its velocity by 10 m/s in 3 seconds.

The average velocity of the accelerating car is (0 + 10) / 2 = 5 m/s

It will advance its position 5 m/s(3 s) = 15 m in the accelerating period.

It takes 5 + 3 = 8 m for the two cars to become side by side.

It would take another 5 + 3 = 8 m for the accelerating car to leave a gap of 3 m between.

The car requires 8 + 8 = 16 m to pass the other safely but the acceleration period only gets him to 15 m.

So despite your saying this is not a YES / NO question, the answer is NO the acceleration is too low or not long enough to meet the required clearances.

Input needed is 10000 J/s / 0.30 = 333333 = J/s

three hours requires 333333(3)(3600) = 360 MJ of energy

360 MJ / 34 MJ/liter = 10.6 liters.

8 0

3 years ago

HEEEEELP!!!!!! :((( help me with this exercise.

kirill [66]

Answer:

See the graph attached with the vectors.

Explanation:

The exercise is to draw the corresponding vectors:

$2\vec a\\\\3\vec c\\\\3\vec d\\\\3\vec f\\\\2\vec b$

Every one is the multiplication of a scalar by a vector.

The result of multiplying a scalar by a vector is a vector with the same direction of the original vector enlarged in a factor equal to the scalar magntitude.

Thus, in a graph the resulting vector is represented with a parallel arrow and pointing in the same direction as the original vector but with a length equal to the original length multiplied by the magnitude of the scalar.

For instance, the vector $2\vec a$ is represented with an arrow in the same direction of $\vec a$ and with twice its length.

The figure attached contains the five requested vectors using the procedure explained above.

7 0

3 years ago

A thin, light wire 75.1 cm long having a circular cross section 0.555 mm in diameter has a 25.4 kg weight attached to it, causin

seraphim [82]

Answer:

(a) 3.23×10⁸ N/m²

(b) 1.46×10⁻³

(c) 2.21×10¹¹ N/m²

Explanation:

(a) Stress = Force/Area.

Stress = F/A................ Equation 1

But,

F = mg................. Equation 2

Where m = mass, and g = acceleration due to gravity

A = πd²/4................. Equation 3

d = diameter of the circular cross section.

Substitute equation 2 and equation 3 into equation 1

Stress = 4mg/πd²............. Equation 4

Given: m = 25.4 kg, d = 0.555 mm = 0.000555 m

Constant: g = 9.8 m/s², π = 3.142

Substitute these values into equation 4

Stress = 4(25.4)(9.8)/(3.142×0.00555²)

Stress = 995.68/(3.08×10⁻⁶)

Stress = 3.23×10⁸ N/m²

(b)

Strain = ΔL/L.............. Equation 5

Where ΔL = extension, L = Length.

Given: ΔL = 1.1 mm = 0.0011 m, L = 75.1 cm = 0.751 m

Substitute into equation 5

Strain = 0.0011/0.751

Strain = 1.46×10⁻³.

(c)

Young modulus = Stress/Strain

Young modulus = 3.23×10⁸/ 1.46×10⁻³

Young modulus = 2.21×10¹¹ N/m²

3 0

3 years ago

A car has a uniform velocity of 108km/h. How far does it travel in 30 seconds?

natita [175]

Velocity=108km/h

Convert to m/s

$\\ \tt\longmapsto 108\times \dfrac{5}{18}$

$\\ \tt\longmapsto 30m/s$

Time=30s.

$\\ \tt\longmapsto Distance=Velocity\times Time$

$\\ \tt\longmapsto Distance=30(30)$

$\\ \tt\longmapsto Distance=900m$

6 0

3 years ago

\. A mixture of gases con-tains oxygen, nitrogen, and water vapor. What physical process could you use to remove the water vapor

Eddi Din [679]

Answer:

Condensation.

Explanation:

The boiling point of water is much higher than that of either nitrogen or oxygen gas . So when the mixture is condensed to a temperature lower than

100°C , water vapor will come out first in the form of water leaving other

elements of mixture in gaseous phase. In this way, water vapor will get separated from others.

3 0

3 years ago