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Allushta [10]
3 years ago
11

These graphs show measurements of the density of air as different sound waves pass a single point.

Physics
2 answers:
inessss [21]3 years ago
7 0

Answer: The graph with the highest density of air.

Explanation: The graphs are missing, but il try to explain this problem anyways.

Soundwaves are mechanical waves, that need a medium to move (commonly, the medium is the air)

As those mechanical waves affect the air, the density of air in some areas increase and in others decrease, and when that "wave of air" impacts a receptor, like your ear, you receive the information of the sound, like pitch and intensity.

As more air impacts the receptor, more "loud" is the noise, and as you may know, density = mass/volume, so as biggest is the density of air in a point, this means that we have more mass of air at that point, which is directly related to the intensity or loudness of the sound wave at that point

Ymorist [56]3 years ago
5 0

Answer: D!

It is the option with the greatest amplitude.

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Which element easily loses one electron to form a positive ion?
olga nikolaevna [1]

Answer/Explanation: As mentioned above, the characteristic chemical property of a metal atom is to lose one or more of its electrons to form a positive ion. However, certain metals lose electrons much more readily than others. In particular, cesium (Cs) can give up its valence electron more easily than can lithium (Li).

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5 0
3 years ago
- Una carga de -5x10-6 C está situada a 20cm delante de otra
saul85 [17]

Answer:

F = 5.625\,N (Fuerza de repulsión/Repulsive force)

Explanation:

La fuerza ejercida entre las dos partículas se calcula por la Ley de Coulomb (The force exerted between the two particles is determined by Coulomb's Law):

F = k \cdot \frac{q_{1}\cdot q_{2}}{r^{2}}

Donde (Where):

k - Constante electrostática, medido en \frac{N\cdot m^{2}}{C^{2}} (Electrostatic constant, measured in \frac{N\cdot m^{2}}{C^{2}}).

q_{1}, q_{2} - Magnitudes de las cargas de cada partícula, medidos en Coulombs. (Magnitudes of charges from each particle, measured in Coulombs).

r - Distancia entre las partículas, medida en metros.

La fuerza electrostática es (Electrostatic force is):

F = \left(9\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot \frac{(5\times 10^{-6}\,C)\cdot (5\times 10^{-6}\,C)}{(0.20\,m)^{2}}

F = 5.625\,N

Dado que las partículas tienen el mismo signo de carga, la fuerza es de repulsión. (Given that both particles have the same charge sign, the force is of repulsive nature)

3 0
3 years ago
the temperature of monoatomic gas was increased from t1=27c to t2=177c. by how many times the internal energy of the gas increas
Romashka [77]

The internal energy increases 1.5 times

Explanation:

the internal energy of a mono atomic gas is given by E= 3/2kT

T1= 27⁰C= 27+273=300 K

T2=177⁰C= 177+273=450 K

E1= 3/2 k (300)

E2=3/2 k (450)

so E2/E1=[3/2 k (450)][3/2 k (300)]

E2/E1=450/300

E2= 1.5 E1

so the internal energy increases by a factor of 1.5

4 0
3 years ago
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