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Allushta [10]
3 years ago
11

These graphs show measurements of the density of air as different sound waves pass a single point.

Physics
2 answers:
inessss [21]3 years ago
7 0

Answer: The graph with the highest density of air.

Explanation: The graphs are missing, but il try to explain this problem anyways.

Soundwaves are mechanical waves, that need a medium to move (commonly, the medium is the air)

As those mechanical waves affect the air, the density of air in some areas increase and in others decrease, and when that "wave of air" impacts a receptor, like your ear, you receive the information of the sound, like pitch and intensity.

As more air impacts the receptor, more "loud" is the noise, and as you may know, density = mass/volume, so as biggest is the density of air in a point, this means that we have more mass of air at that point, which is directly related to the intensity or loudness of the sound wave at that point

Ymorist [56]3 years ago
5 0

Answer: D!

It is the option with the greatest amplitude.

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A baseball is moving at a speed of 2.2m/s when it strikes the catchers glove. The paddding of the glove is compressed by 24mm be
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Average acceleration of the baseball: -101 m/s^2

Explanation:

Since the motion of the baseball is a uniformly accelerated motion, we can use the following suvat equation:

v^2-u^2=2as

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v is the final velocity

a is the acceleration

s is the displacement of the object

For the baseball in this problem, we have:

u = 2.2 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

s = 24 mm = 0.024 m is the displacement of the ball while decelerating

Therefore, we can solve for a to find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{0-2.2^2}{2(0.024)}=-101 m/s^2

where the negative sign means the baseball is slowing down.

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What does the magnitude of centripetal acceleration depend on ?
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Explanation:

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity v and has the magnitude ac=v2r;ac=rω2 a c = v 2 r ; a c = r ω 2 .

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A 10 kg box is 1.3 m above the ground. How much potential energy does it have? (g on Earth of 9.8 m/s?
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Potential energy = mgh
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