Answer:
a = -0.33 m/s² k^
Direction: negative
Explanation:
From Newton's law of motion, we know that;
F = ma
Now, from magnetic fields, we know that;. F = qVB
Thus;
ma = qVB
Where;
m is mass
a is acceleration
q is charge
V is velocity
B is magnetic field
We are given;
m = 1.81 × 10^(−3) kg
q = 1.22 × 10 ^(−8) C
V = (3.00 × 10⁴ m/s) ȷ^.
B = (1.63T) ı^ + (0.980T) ȷ^
Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;
a = qVB/m
a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))
From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^
Thus;
a = -0.33 m/s² k^
The energy that will be released will be 8.95×10^(21) Joules
for comparison, the Nagasaki atom bomb released 8.8*10^(13) Joules
so this meteorite is (8.95×10^(21))/(8.8*10^(13))=100×10^6 (100 million) times more destructive
Answer:
Explanation:
Sphere B and sphere A are touching so they will act as a single body . A positively charged sphere C is brought near sphere B . So there will be induction of charge on sphere B and sphere A . Opposite charge will be induced on nearer sphere and same charge will be induced on distant sphere . Hence sphere B will be negatively charged and sphere A will be positively charged. The amount of charge induced on sphere B and A will be same and it will remain as long as sphere C is kept near sphere B . As soon as sphere C is removed , induced charges will also neutralize each other .
Answer:
the simplest vacuum tube, the diode