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gogolik [260]
2 years ago
15

Hey ppl wassup having a good day?

Chemistry
2 answers:
ludmilkaskok [199]2 years ago
3 0
Yes how about you luv? how’s ur day going
qwelly [4]2 years ago
3 0

Answer:

heyyyy yea i am having a good day! Thanks for asking

Explanation:

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What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273 K under 75 kPa?
Zina [86]
Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure

Use the ideal gas law, given by
pV=nRT \\ or \\  V= \frac{nRT}{p}
where
V = volume
R = 8.3145 J/(mol-K), the gas constant

Therefore,
V= \frac{(12\,mol)(8.3145\, \frac{J}{mol-K} )(273\,K)}{75 \times 10^{3} \, Pa}= 0.3632\,m^{3}

Answer: 0.363 m³
    
5 0
3 years ago
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of a
balandron [24]

Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

To solve this, we can think in the Henderson Hasselbach equation:

pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])

To make the buffer we know:

CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

pKa = 4.74

We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

5.5 - 4.74 = log ([acetate] / 10 mmol)

0.755 = log ([acetate] / 10 mmol)

10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)

5.69 = ([acetate] / 10 mmol)

5.69 . 10 = [acetate] → 56.9 mmoles

6 0
3 years ago
A nugget of GOLD has a mass 9.66 gram and a volume of 0.5 cm3, It's density is<br>grams/cm3 *​
dalvyx [7]

Answer:

P=19.32g/cm³

Explanation:

m=9.66g

v=0.5cm³

P=mass/volume (density formula)

=9.66/0.5

=19.32g/cm³

4 0
3 years ago
DOES ANYONE TAKE ANATOMY AND PHYSIOLOGY I WILL PAY FOR HELPPP!!!!!
lisabon 2012 [21]

Answer:

I take Anatomy and Physiology. Tell me if I can help.

7 0
3 years ago
Who kept scientific experiments from being performed in the middle
Gemiola [76]

Answer:

D. The Church

plz mark me as brainliest

3 0
3 years ago
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