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nevsk [136]
3 years ago
10

Identify the parts of the circulatory system in the diagram:

Chemistry
1 answer:
djverab [1.8K]3 years ago
6 0

In the circulatory system heart is the key organ. Through circulatory system transport of  nutrients, gases such as oxygen to the body and nitrogenous waste away from the body. Human blood circulation is a double circulation as flood flows through two routes that is one for oxygenated blood and the other for deoxygenated blood.

The parts of the circulatory system in the diagram is given below:

a.  Pulmonary artery, carries deoxygenated blood to the lungs from heart.

b. Aorta, carries oxygenated blood to the body tissues from the heart.

c. Inferior vena cava, carries deoxygenated blood from body tissues to the heart.

d. Arterioles, supplies oxygenated blood to the body cells.  

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What element’s valence electrons are located in 5s25p4?
IrinaK [193]
The element is TELLURIUM. Tellurium has atomic number 52 with the electronic configuration of [Kr] 4d10 5s2 5p4. The element belongs to group 16 elements on the periodic table. It exhibits various oxidation states: +2, +4, +6, and -2. +4 is its most common oxidation state.
5 0
3 years ago
A 2.50 L solution contains 5.00 g of NaOH, which has a molecular weight of 40.00
Fantom [35]

Answer:

0.313mol/L

Explanation:

\frac{5.00}{40.00}  \times  2.50 = 0.3125

3 0
3 years ago
How do you write zinc chloride as a chemical formula?
Snezhnost [94]
ZnCl2 is the chemical formula, hope this helps.

7 0
3 years ago
Most homes are built with some form of insulation separating the inside of the home from the outside. What does this insulation
Ad libitum [116K]

Answer:

A. It decreases the temperature difference between the outside and inside.

Explanation:

6 0
2 years ago
When 21.5 g of CH4 gas reacts with 387.5 g O2 gas, how much CO2 is formed?
Doss [256]

Answer:

Mass = 58.96 g

Explanation:

Given data:

Mass of CH₄ = 21.5 g

Mass of O₂ = 387.5 g

Mass of CO₂ formed = ?

Solution:

Chemical equation:

CH₄ + 2O₂       →   CO₂ +  2H₂O

Number of moles of CH₄:

Number of moles = mass / molar mass

Number of moles = 21.5 g/ 16 g/mol

Number of moles = 1.34 mol

Number of moles of O₂ :

Number of moles = mass / molar mass

Number of moles = 387.5 g/ 32 g/mol

Number of moles = 12.1 mol

now we will compare the moles of CO₂  with O₂  and CH₄.

                       O₂             :          CO₂

                          2             :            1

                          12.1          :          1/2×12.1 = 6.05 mol

                        CH₄          :          CO₂

                           1              :            1

                          1.34           :         1.34

Number of moles of CO₂ produced by  CH₄ are less thus it will limiting reactant.

Mass of  CO₂:

Mass = number of moles × molar mass

Mass =  1.34 mol × 44 g/mol

Mass = 58.96 g

8 0
3 years ago
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