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nevsk [136]
3 years ago
10

Identify the parts of the circulatory system in the diagram:

Chemistry
1 answer:
djverab [1.8K]3 years ago
6 0

In the circulatory system heart is the key organ. Through circulatory system transport of  nutrients, gases such as oxygen to the body and nitrogenous waste away from the body. Human blood circulation is a double circulation as flood flows through two routes that is one for oxygenated blood and the other for deoxygenated blood.

The parts of the circulatory system in the diagram is given below:

a.  Pulmonary artery, carries deoxygenated blood to the lungs from heart.

b. Aorta, carries oxygenated blood to the body tissues from the heart.

c. Inferior vena cava, carries deoxygenated blood from body tissues to the heart.

d. Arterioles, supplies oxygenated blood to the body cells.  

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What is potential energy? Give an example please.
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Explanation: Examples ;

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What type of chemical reaction is AgNO3(aq)+KCL(aq) AgCL(s)+KNO3(aq)​
emmasim [6.3K]

Answer:

double replacement reaction or double displacement reaction,

Explanation:

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Classically, these reactions result in the precipitation of one product.

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3 years ago
The carbohydrates seen here contains 3 common elements.They are....
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6 0
3 years ago
Read 2 more answers
Find the standard enthalpy of formation of ethylene, C2H4(g), given the following data: C2H4(g) + 3 O2(g) --&gt; 2CO2(g) + 2 H2O
Brums [2.3K]

Answer : The standard enthalpy of formation of ethylene is, 52.4 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of C_2H_4 will be,

2C(s)+2H_2(g)\rightarrow C_2H_4(g)    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)     \Delta H_1=-1411kJ

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-393.5kJ

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_3=-285.8kJ

Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equation, we get :

(1) 2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)     \Delta H_1=+1411kJ

(2) 2C(s)+2O_2(g)\rightarrow 2CO_2(g)    \Delta H_2=2\times (-393.5kJ)=-787kJ

(3) 2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)    \Delta H_3=2\times (-285.8kJ)=-571.6kJ

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+1411kJ)+(-787kJ)+(-571.6kJ)

\Delta H=52.4kJ

Therefore, the standard enthalpy of formation of ethylene is, 52.4 kJ

7 0
3 years ago
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