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Naya [18.7K]
2 years ago
9

Write the formula and name of the compound formed from the following ionic interactions:

Chemistry
1 answer:
Ainat [17]2 years ago
8 0

Answer:

Explanation:

a ) period 4 noble gas is krypton

isoelectronic with it are Sr ⁺² and Br⁻

compound is SrBr₂

b ) Period 3 noble gas is Argon

isoelectronic with it are Mg⁺² and O⁻²

compound is MgO

c)  2+ ion is the smallest with a filled d subshell is Zn⁺² , smallest halogen

is F⁻

compound is ZnF₂

d )   ions  from the largest and smallest ionizable atoms in Period 2

Li⁺ and  F⁻

compound is LiF

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2 years ago
Determine the mass (in grams) of 8.02 x 1024 atoms of mercury (Hg).
Virty [35]
<h3>Answer:</h3>

2670 g Hg

<h3>General Formulas and Concepts: </h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

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<h3>Explanation: </h3>

<u>Step 1: Define</u>

8.02 × 10²⁴ atoms Hg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Hg - 200.59 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 8.02 \cdot 10^{24} \ atoms \ Hg(\frac{1 \ mol \ Hg}{6.022 \cdot 10^{23} \ atoms \ Hg})(\frac{200.59 \ g \ Hg}{1 \ mol \ Hg})
  2. Divide/Multiply:                                                                                               \displaystyle 2671.42 \ g \ Hg

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2671.42 g Hg ≈ 2670 g Hg

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