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kvasek [131]
3 years ago
5

Are the lines perpendicular? x = 3 and y = 5 *

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

perpendicular line

Step-by-step explanation:

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Solve the following system of equations: 2x + 4y − 3z = −7 3x + y + 4z = −12 x + 3y + 4z = 4
lukranit [14]

2x + 4y − 3z = −7 ---> first equation

3x + y + 4z = −12   ---> second equation

x + 3y + 4z = 4   ---> third equation

We try to eliminate z  and make two equations

Multiply first equation by 4 and second equation by 3. then add both equations

8x + 16y -12z = -28

9x + 3y +12z = -36

----------------------------

17x + 19y = -64   ---------------> equation 4

multiply third equation by -1  and add second and third equation

3x + y + 4z = −12  

-x - 3y - 4z = -4    

-------------------------------------

2x -2y = -16        ---------------> equation 5

Multiply equation 4 by 2 and equation by 19

34x + 38y = -128

38x - 38y = -304

------------------------------------

72x  = -432

Divide by 72 on both sides

x = -6

use equation 2x -2y = -16        ---------------> equation 5

2(-6) - 2y = -16

-12 -2y = -16

-2y = -4

So y = 2

Now plug in 2 for y  and -6 for x

Using any one of the three equations

x + 3y + 4z = 4  

-6 + 3(2) +4z = 4

4z = 4 (divide by 4 on both sides)

So z=1

So x= -6, y = 2  and z= 1





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3 years ago
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BEST ANSWER GETS BRAINLIEST!!
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Step-by-step explanation:

4x+y=20 multiplied by (-4) gives you -16x-4y=-80

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All equations with just X are linear All x^2 are quadratic
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