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Lemur [1.5K]
2 years ago
15

The vertex of this parabola is at (-4,-1). When the y-value is 0, the xvalue is 2

Mathematics
1 answer:
yaroslaw [1]2 years ago
8 0
The standard form for this parabola is x = a(y-k)^2 + h because this is a sideways-opening parabola. Our h and k values for the vertex are (-4, -1). And it goes through (2,0). We just need to solve for the a. Filling in accordingly, 2 = a(0+1)^2-4 so 2 = a - 4. a = 6. A above.

correct answer is 6!
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2/3x + 1/6 = -3/4 x + 1
Marta_Voda [28]
Multiply all terms by 12/1 to get rid of fractions.
8x+2= -9x+12

Add 9x to both sides
17x+2=12

Subtract 2 from both sides
17x=10

Divide both sides by 17
x=10/17

Final answer: x=10/17
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Find the missing side length of JK .
kondor19780726 [428]

Answer:

I'm pretty sure it's 16

Step-by-step explanation:

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What is 11.876 rounded to the nearest tenth?
vesna_86 [32]

Answer:

11.9

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
Need help with this question ​
Andreas93 [3]

The Domain is (-∞, -2) U (-2, 2) U (2, ∞) and Range is (-∞, -2) U [-1, ∞) and x-intercept = (-1.5, 0), (1.5, 0) and y-intercept = (0, -1).

<h3>What is a conic section?</h3>

It is defined as the curve which is the intersection of cone and plane. There are three major conic sections; parabola, hyperbola, and ellipse (circle is a special of type of ellipse).

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

From the graph:

a) The domain: all values of x

The range: all values of y

Except: Values at asymptotes are excluded.

Domain = (-∞, -2) U (-2, 2) U (2, ∞)

Range = (-∞, -2) U [-1, ∞)

b)

x-intercept = (-1.5, 0), (1.5, 0)

y-intercept = (0, -1)

c) Horiznotal asymptotes: y = -2

d)Vetical asymptotes: x = -2, x = 2

e) Oblique asymptotes: There is no oblique asymptotes

Thus, the Domain is (-∞, -2) U (-2, 2) U (2, ∞) and Range is (-∞, -2) U [-1, ∞) and x-intercept = (-1.5, 0), (1.5, 0) and y-intercept = (0, -1).

Learn more about the conic section here:

brainly.com/question/8412465

#SPJ1

7 0
2 years ago
A baker has 6 pounds of sugar. He divides into 3 containers. He then uses 1 container to bake pies.
butalik [34]

Step-by-step explanation:

If the question is how much sugar contains pie, then do it like this:

6:3=2

So in one container you have 2 pounds of sugar. And if you use 1 container for a pie you will use : 2 pounds of sugar for pie.

If question is how much sugar does he have after that, it would be:

6-2=4 pounds of sugar or

3-1= 2 containers of sugar

4 0
2 years ago
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