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sashaice [31]
4 years ago
15

A bus travels 280 km south along a straight path with an average velocity of 88 km/h to the south. The bus stops for 24 min, the

n it travels 210 km south with an average velocity of 75 km/h to the south. a. How long does the total trip last? b. What is the average velocity for the total trip?
Physics
2 answers:
loris [4]4 years ago
8 0

Answer:

yes yes yes yes

Explanation:

because

IgorC [24]4 years ago
3 0

Answer:

76.78 km/h To calculate the average velocity for the total trip, you need to first determine the total distance traveled and the total time taken. First, let's calculate the total distance traveled. The trip consists of 2 legs. The 1st leg is 280 km and the 2nd leg is 210 km. So the total distance is 280 km + 210 km = 490 km. Now you need to calculate the total time taken. For this problem, there are 3 intervals that need to be accounted for. The travel time for the 1st leg, the duration of the rest stop in the middle, and the travel time for the 2nd leg. The travel time for both legs is calculated by dividing the distance traveled by the average speed. So for the first leg we have 280 km / (88 km / h) = 3.181818 h The 2nd leg is 210 km / (75 km/h) = 2.8 h The rest stop in hours is 24 min / (60 min/h) = 0.4 h The total time is 3.181818 h + 2.8 h + 0.4 h = 6.381818 h The average velocity is the distance divided by the time, giving: 490 km / (6.381818 h) = 76.78 km/h

Explanation:

Hope this helps!!

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stellarik [79]

Answer:

Circular path

Explanation:

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3 0
3 years ago
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Carbon is an element on the periodic table while carbon dioxide is a compound. This is because carbon dioxide is ....
ivanzaharov [21]

Answer:

the last one

Explanation:

because it is composed of atoms of two or more elements and carbon is a pure substance composed of only one type of atoms

6 0
3 years ago
At some airports there are speed ramps to help passengers get from one place to another. A speed ramp is a moving conveyor belt
Amanda [17]

Answer:

The time taken is t_s = 31.16 s

Explanation:

From the question we are told that

   The length of the speed ramp is L = 104m

     The speed of the speed ramp is v_r  = 2.1 m/s

      The time taken to cover the distance is t = 84 s

     

The walking speed( when not on the speed ramp)  required to  cover the 104m is mathematically represented as

                     v_w = \frac{L}{t}

Substituting values

                      v_w = \frac{104}{84}

                            = 1.238 m/s

The speed required to cover the 104m distance when on a speed speed ramp  is mathematically represented as

     v = The\ walking\ speed  +  speed \ of \ the \ speed \ ramp

 substituting values

               v = 2.1 + 1.238

               v = 3.338 m/s

Now the time taken to travel the 104m distance when walking on the speed ramp is mathematically evaluated as

                t_s = \frac{L}{v}

                     = \frac{104}{3.338}

                     t_s = 31.16 s

             

4 0
3 years ago
Read 2 more answers
Find the elongation produced in a copper wire of length 2m and radius 5mm, when suspended by a block
igomit [66]

Answer:

0.104 m

Explanation:

Stress, \sigma=\frac {F}{A}

Where F is force and A is area. Also, F=mg where m is mass and g is acceleration due to gravity

Area= \pi r^{2}

Strain=\frac {\triangle l}{l} where \triangle l is the elongation and l is the original length

E=\frac {stress}{strain}=\frac {\frac {F}{A}}{\frac {\triangle l}{l}}=\frac {Fl}{A\triangle l}

Making \triangle l the subject then

\triangle l=\frac {Fl}{AE}=\frac{mg l}{\pi r^{2} E}

By substituting the given values and taking g as 9.81 then

\triangle l=\frac {Fl}{AE}=\frac{500\times 9.81\times 2 m}{\pi \times 0.005^{2}\times 1.2\times 10^{9}}=0.104087333  m\approx 0.104 m

3 0
3 years ago
Two charged particles are projected into a magnetic field that is perpendicular to their initial velocities. If the charges are
Svetllana [295]

Answer:

The two charged particles are opposite charge (one positive, the other negative)

Explanation:

This can be explained through Fleming's left hand rule. As we know in Fleming's LH rule

Thumb: represent motion of the charge

Fore finger: direction of magnetic field

Centre finger: direction of current

In this case, the direction of magnetic field is in one way (perpendicular to direction of the particles motion)

If the charge is positive, equivalently it's direction is the same as the direction of current. If the charge is negative, it's direction is opposite the direction of current.

Using the fleming left hand rule, we'll see that as we change the direction of current without changing the direction of field, the direction of motion will change towards the opposite way.

For example, let's say the particles is moving away from you and the magnetic field is from left to right:

If the charge is positive (hence direction of current is away from you), the particles will move downward.

If the charge is negative (hence direction of current is toward you), the particles will move upward.

With these evidence, no doubt that the two particles have different charges.

7 0
3 years ago
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