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3 years ago

9

How do i find the number of leptons in an atom??

1 answer:

Serjik [45]3 years ago

8 0

Answer:

In particle physics, a lepton is an elementary particle of half-integer spin (spin 1⁄2) that does not undergo strong interactions.[1] Two main classes of leptons exist: charged leptons (also known as the electron-like leptons or muons), and neutral leptons (better known as neutrinos). Charged leptons can combine with other particles to form various composite particles such as atoms and positronium, while neutrinos rarely interact with anything, and are consequently rarely observed. The best known of all leptons is the electron.

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Which of the following is a correct equation for total energy?

sweet [91]

Answer:

Total energy=Kinetic energy+Potential energy

Explanation:

the total energy will be obtained from the energy of an object in motion and the energy stored in the object

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3 years ago

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Samples of different materials, A and B, have the same mass, but the sample

Effectus [21]

Answer:

B. The particles that make up material B have more mass than the

particles that make up material A.

Explanation:

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3 years ago

A cylinder with a piston contains 0.200 mol of nitrogen at 1.50×105 Pa and 320 K . The nitrogen may be treated as an ideal gas.

Alja [10]

Answer:

$Q = -105 J$

Also we know that for cyclic process change in internal energy is always ZERO

Explanation:

First gas is compressed isobarically such that its volume is half of initial volume

So its temperature is also half

So heat given in this process is given as

$Q = nC_p \Delta T$

for diatomic gas we have

$C_p = \frac{7}{2} R$

so we will have

$Q = 0.200(\frac{7}{2}R)(160 - 320)$

$Q = -930.7 J$

Now in adiabatic process heat is not transferred

so in this process

$Q = 0$

so we have

$T_1V_1^{1.4-1} = T_2V_2^{1.4-1}$

$(160)(\frac{V}{2})^{0.4} = T_2(V)^{0.4}$

$T_2 = 121.26 K$

Now it is again reached to original pressure

so temperature will become initial temperature

so heat given in that part

$Q_3 = nC_v\Delta T$

here we know that

$C_v = \frac{5}{2}R$

$Q_3 = (0.200)(\frac{5}{2}R)(320 - 121.26)$

$Q_3 = 825.76 J$

So total heat given to the system is

$Q = -930.7 + 0 + 825.76$

$Q = -105 J$

Also we know that for cyclic process change in internal energy is always ZERO

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3 years ago

In what way are liquids different from

andrew11 [14]

Answer: The answer is C

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3 years ago

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An upward force of 18 N is applied via a string to lift a ball with a mass of 1.5 kg.

valentinak56 [21]

net force = applied force + gravity = 18N+(1.5kg)(-9.8m/s^2) = 3.3N

Force=mass times acceleration
acceleration=Force/mass
acceleration=3.3/1.5 m/s^2
acceleration=2.2m/s^s

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3 years ago