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Ivenika [448]
3 years ago
6

I started walking at 4pm when I finished the hour hand of the clock turned 90 degrees what time did I finish

Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

7 P.M.

Step-by-step explanation:

Time at which the walk was begun = 4 p.m.

Finished after rotating the clock 90° i.e. = 3 hours

Thus,

The time at which the task finished = 4 p.m. + 3hours

= 7:00 PM

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(2a^2b + 3ab^2 - b^3) - (4b^3 - 3ab^2 -6a^2b)
skelet666 [1.2K]

<em>Hi there!</em>

<em>~</em>

<em></em>(2a^2b+3ab^2-b^3)-(4b^3-3ab^2-6a^2b)<em></em>

<em>Distribute the Negative Sign:</em>

<em></em>= 2a^2 b + 3ab^2 - b^3 + -1(4b^3 - 3ab^2 - 6a^2b)\\= 2a^2 b + 3ab^2 + - b^3 + -1 (4b^3) + -1 (-3ab^2) + -1 (-6a^2b)\\= 2a^2 b + 3ab^2 + -b^3 + -4b^3 + 3ab^2 + 6a^2 b<em></em>

<em>Combine Like Terms:</em>

<em></em>= 2a^2 b + 3ab^2 - b^3 + -4ab^3 + 3ab^2 + 6a^2 b\\= (2a^2 b + 6a^2 b) + ( 3ab^2 + 3ab^2) + (-b^3 + -4b^3) \\= 8a^2 b + 6ab^2 + -5b^3<em></em>

<em>Answer : </em>8a^2 b + 6ab^2 + -5b^3<em></em>

<em>Hope this helped you!</em>

7 0
3 years ago
Quis<br><br>Hallo my name ia rafli, from Indonesian​
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
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City A is 10 miles from city B and 5 miles from city C. Cities A, B, and C form a right triangle at A. A road connects cities B
laila [671]

Answer:

11.18 miles

Step-by-step explanation:

The sides of a right triangle a, b, c are related by the equation

a^2 + b^2 = c^2

where c is the longest side of the triangle

Hence given that A connects B and C directly and forms a right angle at A

5^2 + 10^2 = c^2

Where c is the length of the road

25 + 100 = c^2

125 = c^2

c = 125^1/2

= 11.18 miles

3 0
3 years ago
Assume you are given two right triangle with congruent hypotenuses and wish to show that they are congruent
uysha [10]
If you can find one leg of a triangle to be congruent to a leg on the other triangle, then you can use the HL (hypotenuse leg) theorem. If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and a leg of another right triangle, then the triangles are congruent.
7 0
3 years ago
Find the midpoint and distance between each pair of points, with easy explanation and work !! will give brainliest.
rewona [7]
If we have 2 coordinates say: (x1,y1) and (x2,y2)

Then the formula for the midpoint is:

((x1+x2)/2,(y1+y2)/2)

And the formula for the distance is:

Sqrt((x2-x1)^2+(y2-y1)^2)

So here we have (-1,-4) and (-7,4)

The midpoint is:

((-1+-7)/2,(-4+4)/2) = (-8/2,0/2) = (-4,0)

The distance is:

Sqrt((-7- -1)^2+(4- -4)^2)
= sqrt((-6^2)+(8^2))
=sqrt(36+64)
=sqrt(100)
=10
6 0
3 years ago
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