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3 years ago

6. If 981 mL of a gas is heated from 335 K at constant pressure and the volume

Chemistry

1 answer:

storchak [24]3 years ago

3 0

Answer:

1.5L

Explanation:

The new volume can be found by using the formula for Boyle's law which is

p1v1=p2v2

Since we are finding the new volume

v2= p1v1/p2

From the question we have

v2= 5x3/10=15/10= 3/5

We have the final answer as

1.5 L

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If 10.0g of oxygen reacts with 10.0g of hydrogen, how many grams of water can be

rusak2 [61]

Answer:

the answer is 90g

Explanation:

2g of H2 produce 18g of H2O/10.0g of H2 to produce x the answer is 90g

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3 years ago

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Nutka1998 [239]

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3 years ago

The following reactions take place in the ozone layer by the absorption of ultraviolet light.

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Answer:

Option B will require a shorter wave length of light.

Explanation:

The bonding between Ozone (O3) and Oxygen (O2) can be used to explain why the breaking of oxygen into Oxygen radicals will require a shorter wave length.

The bond between Oxygen (O2) is a double bond while Ozone (O3) has an intermediate bond between a double bond and a single bond.

The bond order of Oxygen (O2) is equals 2 while that of Ozone (O3) is 1.5. Since the bond order of oxygen is higher, it will require more energy to break the bond compared to breaking the Ozone (O3) bond.

Recall that Energy is inversely proportional to wave length.

So it will require a shorter wave length to break the Oxygen (O2) into its radicals.

5 0

3 years ago

A rectangular corral of widths Lx = L and Ly = 2L contains seven electrons. What is the energy of (a) the first excited state, (

DiKsa [7]

Answer:

See explaination

Explanation:

The invariant mass of an electron is approximately9. 109×10−31 kilograms, or5. 489×10−4 atomic mass units. On the basis of Einstein's principle of mass–energy equivalence, this mass corresponds to a rest energy of 0.511 MeV.

Check attachment for further solution to the exercise.

3 0

3 years ago

The activation energy for proline isomerization of a peptide depends on the identity of the preceding residue and obeys Arrheniu

MAVERICK [17]

Answer:

Activation energy of phenylalanine-proline peptide is 66 kJ/mol.

Explanation:

According to Arrhenius equation- $k=Ae^{\frac{-E_{a}}{RT}}$ , where k is rate constant, A is pre-exponential factor, $E_{a}$ is activation energy, R is gas constant and T is temperature in kelvin scale.

As A is identical for both peptide therefore-

$\frac{k_{ala-pro}}{k_{phe-pro}}=e^\frac{[E_{a}^{phe-pro}-E_{a}^{ala-pro}]}{RT}$

Here $\frac{k_{ala-pro}}{k_{phe-pro}}=\frac{0.05}{0.005}$ , T = 298 K , R = 8.314 J/(mol.K) and $E_{a}^{ala-pro}=60kJ/mol$

So, $\frac{0.05}{0.005}=e^{\frac{[E_{a}^{phe-pro}-(60000J/mol)]}{8.314J.mol^{-1}.K^{-1}\times 298K}}$

$\Rightarrow$ $E_{a}^{phe-pro}=65705J/mol=66kJ/mol$ (rounded off to two significant digit)

So, activation energy of phenylalanine-proline peptide is 66 kJ/mol

7 0

3 years ago