<h2>The net ionic equation that correspond to Fe(ClO4)2 +Na2CO3 is</h2>
<u>Fe ^2+(aq) +CO3^2-(aq) → FeCO3 (s)</u>
<h3>Explanation</h3><h3 /><h3>write the balance chemical equation</h3>
Fe(ClO4)2 (aq) + Na2CO3(aq)→ FeCO3 (s) + 2 NaClO4
<h3>write the ionic equation</h3>
Fe^2+(aq) + 2ClO4 ^-(aq) + 2Na^+(aq) +CO3^2- (aq) → FeCO3 (s) + 2Na^+ + 2ClO4^-
<h3>cancel the spectator ions in both side</h3>
- that is ( 2ClO4^- and 2Na+)
the ionic equation is therefore
<u>Fe^2+(aq) + CO3^2- →FeCo3(s)</u>
The correct answer here would be C.
<span>9.40x10^19 molecules.
The balanced equation for ammonia is:
N2 + 3H2 ==> 2NH3
So for every 3 moles of hydrogen gas, 2 moles of ammonia is produced. So let's calculate the molar mass of hydrogen and ammonia, starting with the respective atomic weights:
Atomic weight nitrogen = 14.0067
Atomic weight hydrogen = 1.00794
Molar mass H2 = 2 * 1.00794 = 2.01588 g/mol
Molar mass NH3 = 14.0067 + 3 * 1.00794 = 17.03052 g/mol
Moles H2 = 4.72 x 10^-4 g / 2.01588 g/mol = 2.34140921086573x10^-4 mol
Moles NH3 = 2.34140921086573x10^-4 mol * (2/3) = 1.56094x10^-4 mol
Now to convert from moles to molecules, just multiply by Avogadro's number:
1.56094x10^-4 * 6.0221409x10^23 = 9.400197448261x10^19
Rounding to 3 significant figures gives 9.40x10^19 molecules.</span>
Answer: Think and you will get it right!
Explanation:
To find the mass percent composition of an element, divide the mass contribution of the element by the total molecular mass. This number must then be multiplied by 100% to be expressed as a percent.
<span><span>V. C. Wynne-Edwards and Konrad Lorenz were
the first authors to raise the concept of
altruism</span><span>. This was later
reiterated by </span>David Sloan Wilson, E. O. Wilson and Elliott Sober<span> in 1994 whose works referred to social organisms such as ants</span></span>.
