Answer:
Look at the explanation.
I'll be online so let me know if you still need help.
Step-by-step explanation.
A system of equations is basically two or more equations that rely on each other. If a solution for a variable is 2, it has to work for the other equation.
The substitution is basically plugging in the y value to y = 8x + 10
If y = 2
and also y = 8x + 10
What do you think the substitution is?
8-22a
2(4-11a)
Take the largest number you can factor out of 8&22
Answer:
Simplify the expression; 2^3 x 2^2
<u>A. 2^5
</u>
B. 4^6
C. 4^5
D. 2^6
Step-by-step explanation:
You add the powers together since you are multiplying.
Answer:
tan(2u)=[4sqrt(21)]/[17]
Step-by-step explanation:
Let u=arcsin(0.4)
tan(2u)=sin(2u)/cos(2u)
tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]
If u=arcsin(0.4), then sin(u)=0.4
By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.
This also implies cos(u)=sqrt(0.84) since cosine is positive.
Plug in values:
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]
tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]
tan(2u)=[(40)(sqrt(0.84)]/[34]
tan(2u)=[(20)(sqrt(0.84)]/[17]
Note:
0.84=0.04(21)
So the principal square root of 0.04 is 0.2
Sqrt(0.84)=0.2sqrt(21).
tan(2u)=[(20)(0.2)(sqrt(21)]/[17]
tan(2u)=[(20)(2)sqrt(21)]/[170]
tan(2u)=[(2)(2)sqrt(21)]/[17]
tan(2u)=[4sqrt(21)]/[17]
