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3 years ago

When a vechicle is being pushed manually, it should ___

Engineering

2 answers:

Natali5045456 [20]3 years ago

7 0

Answer:

go forward or move

Explanation:

Aleks [24]3 years ago

7 0

The vehicle should be in neutral

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Two resistors, with resistances R1 and R2, are connected in series. R1 is normally distributed with mean 65 and standard deviati

Sedbober [7]

Answer:

n this question, we are asked to find the probability that

R1 is normally distributed with mean 65 and standard deviation 10

R2 is normally distributed with mean 75 and standard deviation 5

Both resistor are connected in series.

We need to find P(R2>R1)

the we can re write as,

P(R2>R1) = P(R2-R1>R1-R1)

P(R2>R1) = P(R2-R1>0)

P(R2>R1) = P(R>0)

Where;

R = R2 - R1

Since both and are independent random variable and normally distributed, we can do the linear combinations of mean and standard deviations.

u = u2-u1

u = 75 - 65 = 10ohm

sd = √sd1² + sd2²

sd = √10²+5²

sd = √100+25 = 11.18ohm

Now we will calculate the z-score, to find P( R>0 )

Z = ( X -u)/sd

the z score of 0 is

z = 0 - 10/11.18

z= - 0.89

4 0

4 years ago

How much power is needed to operate a Carnot heat pump if the pump receives heat 10°C and delivers 50 kW of heat at 40°C? at A)

mariarad [96]

Answer:

Power needed to pump=4.79 KW.

Explanation:

Given that: $T_{1}=283K,T_{2}=313K,Q_{H}=50KW$

We know that coefficient of performance of heat pump

COP= $\dfrac{T_{H}}{T_{H}-T_{L}}$

So COP= $\dfrac{313}{313-283}$

COP=10.43

COP= $\frac{Q_{H}}{W_{in}}$

10.43 = $\frac{50}{W_{in}}$

$W_{in}$ =4.79 KW

So power needed to pump=4.79 KW.

3 0

4 years ago

Which of the following would NOT have to be cleaned after each use?

Delicious77 [7]

Answer:

OD.

nail brush

Explanation:

hope this will help you

4 0

3 years ago

Read 2 more answers

In a planetary geartrain with a form factor of 8, the sun gear rotates clockwise at 5 rad⁄s and the ring gear rotates clockwise

lina2011 [118]

Answer:

D. N= 11. 22 rad/s (CW)

Explanation:

Given that

Form factor R = 8

Speed of sun gear = 5 rad/s (CW)

Speed of ring gear = 12 rad/s (CW)

Lets take speed of carrier gear is N

From Algebraic method ,the relationship between speed and form factor given as follows

$\dfrac{N_{sun}-N}{N_{ring}-N}=-R$

here negative sign means that ring and sun gear rotates in opposite direction

Lets take CW as positive and ACW as negative.

Now by putting the values

$\dfrac{N_{sun}-N}{N_{ring}-N}=-R$

$\dfrac{5-N}{12-N}=-8$

N= 11. 22 rad/s (CW)

So the speed of carrier gear is 11.22 rad/s clockwise.

8 0

3 years ago

What would be the most likely scale factor to use for an n-gauge model train setup? (An n-gauge layout uses locomotives that are

slega [8]

A or b for sure brother

8 0

3 years ago