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Verizon [17]
3 years ago
13

In a planetary geartrain with a form factor of 8, the sun gear rotates clockwise at 5 rad⁄s and the ring gear rotates clockwise

at 12 rad⁄s. At what speed does the carrier gear rotate? A. 12.9 rad⁄s clockwise B. 12.9 rad⁄s counterclockwise C. 11.2 rad⁄s counterclockwise D. 11.2 rad⁄s clockwise E. 5.8 rad⁄s clockwise
Engineering
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

D. N= 11. 22 rad/s (CW)

Explanation:

Given that

Form factor R = 8

Speed of sun gear = 5 rad/s (CW)

Speed of ring gear = 12 rad/s (CW)

Lets take speed of carrier gear is N

From Algebraic method ,the relationship between speed and form factor given as follows

\dfrac{N_{sun}-N}{N_{ring}-N}=-R

here negative sign means that ring and sun gear rotates in opposite direction

Lets take CW as positive and ACW as negative.

Now by putting the values

\dfrac{N_{sun}-N}{N_{ring}-N}=-R

\dfrac{5-N}{12-N}=-8

N= 11. 22 rad/s (CW)

So the speed of carrier gear is 11.22 rad/s clockwise.

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The heat rate is essentially the reciprocal of the thermal efficiency. a)- True b)- False
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Answer:

a). TRUE

Explanation:

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Which contribution of Science is the most important discovery of man? Explain why?​
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3 years ago
A heavy-duty electrical resistor is 2cm in diameter by 16cm long. 5 amps of current through it heats the resistor to 100°C, and
Olenka [21]

Answer:

The convective coefficient is 37.3 W/m²K.  

Explanation:

Use Newton’s law of cooling to determine the heat transfer coefficient. Assume there is no heat transfer from the ends of electric resistor. Heat is transferred from the resistor curved surface.  

Step1

Given:

Diameter of the resistor is 2 cm.

Length of the resistor is 16 cm.

Current is 5 amp.

Voltage is 6 volts.

Resistor temperature is 100°C.

Room air temperature is 20°C.

Step2

Electric power from the resistor is transferred to heat and this heat is transferred to the environment by means of convection.

Power of resistor is calculated as follows:

P=VI

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Step3

Newton’s law of cooling is expressed as follows:

Q=h\times \pi DL(T_{r}-T_{\infty})

Here, h is the convection heat coefficient and \pi DL is the exposed surface area of the resistor.

Substitute the values as follows:

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3 years ago
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