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3 years ago

Please Its urgent I need your HELP!!!!!!!!!!!!!!!!!!!!!!!

Physics

1 answer:

ozzi3 years ago

4 0

Raising the temperature results in the radiator giving off photons of high-energy ultraviolet light. As heat is added, the radiator emits photons across a wide range of visible-light frequencies

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For a freely falling object weighing 3 kg : A. what is the object's velocity 2 s after it's release. B. What is the kinetic ener

Fed [463]

A) 19.6 m/s (downward)

B) 576 J

C) 19.6 m

D) Velocity: not affected, kinetic energy: doubles, distance: not affected

Explanation:

An object in free fall is acted upon one force only, which is the force of gravity.

Therefore, the motion of an object in free fall is a uniformly accelerated motion (constant acceleration). Therefore, we can find its velocity by applying the following suvat equation:

$v=u+at$

where:

v is the velocity at time t

u is the initial velocity

$a=g=9.8 m/s^2$ is the acceleration due to gravity

For the object in this problem, taking downward as positive direction, we have:

$u=0$ (the object starts from rest)

$a=9.8 m/s^2$

Therefore, the velocity after

t = 2 s

is:

$v=0+(9.8)(2)=19.6 m/s$ (downward)

The kinetic energy of an object is the energy possessed by the object due to its motion.

It can be calculated using the equation:

$KE=\frac{1}{2}mv^2$

where

m is the mass of the object

v is the speed of the object

For the object in the problem, at t = 2 s, we have:

m = 3 kg (mass of the object)

v = 19.6 m/s (speed of the object)

Therefore, its kinetic energy is:

$KE=\frac{1}{2}(3)(19.6)^2=576 J$

In order to find how far the object has fallen, we can use another suvat equation for uniformly accelerated motion:

$s=ut+\frac{1}{2}at^2$

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

For the object in free fall in this problem, we have:

u = 0 (it starts from rest)

$a=g=9.8 m/s^2$ (acceleration of gravity)

t = 2 s (time)

Therefore, the distance covered is

$s=0+\frac{1}{2}(9.8)(2)^2=19.6 m$

Here the mass of the object has been doubled, so now it is

M = 6 kg

For part A) (final velocity of the object), we notice that the equation that we use to find the velocity does not depend at all on the mass of the object. This means that the value of the final velocity is not affected.

For part B) (kinetic energy), we notice that the kinetic energy depends on the mass, so in this case this value has changed.

The new kinetic energy is

$KE'=\frac{1}{2}Mv^2$

where

M = 6 kg is the new mass

v = 19.6 m/s is the speed

Substituting,

$KE'=\frac{1}{2}(6)(19.6)^2=1152 J$

And we see that this value is twice the value calculated in part A: so, the kinetic energy has doubled.

Finally, for part c) (distance covered), we see that its equation does not depend on the mass, therefore this value is not affected.

5 0

3 years ago

The monomer used as the building block in polyethylene is? Ethene, ethane, monoethane, amino acids?

LuckyWell [14K]

<span>it's ethene and not an amino acid!!! amino acids form proteins as their polymers. </span>

6 0

4 years ago

Which feature of a human community is similar to a niche in a biological community?

pogonyaev

Answer: C. occupation

7 0

4 years ago

You attach a meter stick to an oak tree, such that the top of the meter stick is 2.07 meters above the ground. Later, an acorn f

ra1l [238]

Answer:

5.05 m

Explanation:

length of stick (L) = 1 m

distance from the top of the stick to the ground (d) = 2.07 m

time taken for corn to travel the length of the stick (t) = 0.121 s

acceleration due to gravity (a) = 9.8 m/s^{2}

we can get the distance in four stages.

Finding the velocity the corn was moving at from $s=vt+0.5at^{2}$

where s = length of stick, t = time, a = acceleration due to gravity

$s=vt+0.5at^{2}$

1 = 0.121u + (0.5 x 9.8 x 0.121 x 0.121)

1 = 0.121v + 0.0717

1 - 0.0717 = 0.121v

v = 7.67 m/s

Using the velocity above to find the time it took for the corn to fall to the top of the stick from the formula v = u + at' where:

v = final velocity = 7.67 m/s

u = initial velocity = 0 m/s since it was initially at rest

a = acceleration due to gravity

t' = time taken to fall to the top of the stick

7.67 = 0 + (9.8 x t')

t' = 7.67 / 9.8 = 0.78 s

using the time above to find the distance between the branch the corn falls from and the top of the stick using $s=vt+0.5at^{2}$ where:

s = distance

v = initial velocity = 0 m/s since it was initially at rest

t = time = 0.78 s

a = acceleration due to gravity = 9.8

s = 0 + (0.5 x 9.8 x 0.78 x 0.78)

s = 2.98 m

Add the distance between the branch the corn falls from and the top of the stick and the distance from the top of the stick to the ground.

2.98 + 2.07 = 5.05 m

5 0

3 years ago

A sample of hydrogen gas will behave most like an ideal gas under the conditions of(1) low pressure and low temperature(2) low p

docker41 [41]

Ideal gas has several important properties that must be followed by real gases to behave like an ideal gas

so here we can say

1. all gas molecules moves at very fast speed in random direction

2. there should not be any interaction force between molecules of gas

3. all gas molecules must have to follow Newton's II law

4. There is no effect of gravity on the molecules of gas

so here if all above conditions are followed by gas then

the condition must be followed only at low pressure and high temperature

so correct answer is

<em>(2) low pressure and high temperature</em>

5 0

3 years ago