Answer:
Since it is falling freely, the only force on it is its weight, w.
w = m × g = 250 kg × 9.8 m/s^2 = 2450 Newton/N
Answer:
the tension in the string an instant before it broke = 34 N
Explanation:
Given that :
mass of the ball m = 300 g = 0.300 kg
length of the string r = 70 cm = 0.7 m
At highest point, law of conservation of energy can be expressed as :
![\frac{1}{2} mv^2 = mgh\\\\v = \sqrt{2gh}\\\\v = \sqrt{2*(9.8 \ m/s^2)*(6.00 \ m - 2.00 \ m)}\\\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20mv%5E2%20%3D%20mgh%5C%5C%5C%5Cv%20%3D%20%5Csqrt%7B2gh%7D%5C%5C%5C%5Cv%20%3D%20%5Csqrt%7B2%2A%289.8%20%5C%20%20m%2Fs%5E2%29%2A%286.00%20%5C%20m%20-%202.00%20%5C%20m%29%7D%5C%5C%5C%5C)
![v = 8.854 \ m/s](https://tex.z-dn.net/?f=v%20%3D%208.854%20%5C%20m%2Fs)
The tension in the string is:
![T = \frac{mv^2}{r}\\\\T = \frac{(0.300 \ kg)*(8.854 \ m/s^2)}{0.70 \ m}\\\\T = 33.59 N\\\\T = 34 \ N](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7Bmv%5E2%7D%7Br%7D%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B%280.300%20%5C%20kg%29%2A%288.854%20%5C%20m%2Fs%5E2%29%7D%7B0.70%20%5C%20m%7D%5C%5C%5C%5CT%20%3D%2033.59%20N%5C%5C%5C%5CT%20%3D%2034%20%5C%20N)
Thus, the tension in the string an instant before it broke = 34 N
The correct option is C) The angle between the vectors is 120°.
Why?
We can solve the problem and find the correct option using the Law of Cosine.
Let A and B, the given two sides and R the resultant (sum),
Then,
![R=A=B](https://tex.z-dn.net/?f=R%3DA%3DB)
So, using the law of cosines, we have:
![R^{2}=A^{2}+B^{2}+2ABCos(\alpha)\\ \\A^{2}=A^{2}+A^{2}+2*A*A*Cos(\alpha)\\\\0=A^{2}+2*A^{2}*Cos(\alpha)\\\\Cos(\alpha)=-\frac{A^{2}}{2*A^{2}}=-\frac{1}{2}\\\\\alpha =Cos(-\frac{1}{2})^{-1}=120\°](https://tex.z-dn.net/?f=R%5E%7B2%7D%3DA%5E%7B2%7D%2BB%5E%7B2%7D%2B2ABCos%28%5Calpha%29%5C%5C%20%5C%5CA%5E%7B2%7D%3DA%5E%7B2%7D%2BA%5E%7B2%7D%2B2%2AA%2AA%2ACos%28%5Calpha%29%5C%5C%5C%5C0%3DA%5E%7B2%7D%2B2%2AA%5E%7B2%7D%2ACos%28%5Calpha%29%5C%5C%5C%5CCos%28%5Calpha%29%3D-%5Cfrac%7BA%5E%7B2%7D%7D%7B2%2AA%5E%7B2%7D%7D%3D-%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Calpha%20%3DCos%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B-1%7D%3D120%5C%C2%B0)
Hence, we have that the angle between the vectors is 120°. The correct option is C) The angle between the vectors is 120°
Have a nice day!
Answer:
With an Environmental Engineering and a broadcasting minor
You can work as an On Air personality that host programs that provide your audience with documentaries about the environments and project carried out by Environmental Engineer
and also you can work as a journalist that explore the world making research that will preserve the environment and leveraging the media as a broadcaster to provide this research findings as a video for you audience
Explanation:
In order to get a better understanding let define some terms
Environmental Engineer
:
Environmental engineers resolve and help prevent environmental problems. They work in many areas, including air pollution control, industrial hygiene, toxic materials control, and land management. The duties of an environmental engineer range from planning and designing an effective waste treatment plant to studying the effects of acid rain on a particular area. An environmental engineer is sometimes required to work outdoors, though most of her work is done in a laboratory or office setting. Career opportunities for environmental engineers exist in consulting, research, corporate, and government positions.
Broadcasting:
Broadcasting is the distribution of audio or video content to a dispersed audience via any electronic mass communications medium, but typically one using the electromagnetic spectrum (radio waves), in a one-to-many model.
Continuous. Discrete values are values like 1, 2, 3, 4, etc. - they're values that are <em>distinct</em>, and typically there's some idea of a <em>next </em>and a <em>previous </em>value. When we're counting whole numbers, there's a definitive answer to which number comes after, and which number comes before. With continuous values, there's no real "next" or "last" value.
Motion is measured with <em>continuous </em>values; a train might move 300 yards in 1 minute, but we can look at smaller and smaller chunks of time to keep getting shorter and shorter distances. There is no <em />"next" distance the train moves after those 300 yards - it just doesn't make sense for there to be.
It's also measured <em>quantitatively</em>, not <em>qualitatively</em>. This just means that we can use numerical values to measure it, rather than other descriptors like color, smell, or taste.