Answer:
ELASTIC collision
kinetic energy is conservate
Explanation:
As the ball bounces to the same height, it can be stated that the impact with the floor is ELASTIC.
As the floor does not move the conservation of the moment
po = pf
-mv1 = m v2
- v1 = v2
So the speed with which it descends is equal to the speed with which it rises
Therefore the kinetic energy of the ball before and after the collision is the same
Answer:
1225 J
Explanation:
The Gravitational potential energy (PEG) gained by a mass lifted above the ground is given by
where
m is the mass
g = 9.8 m/s^2 is the acceleration due to gravity
h is the height at which the object has been lifted
In this problem, we have
m = 250 kg
h = 0.5 m
So, the PE of the object is
Elastic potential energy.
When you stretch a rubber band it has the "potential" to do work, to fly in a given direction. In doing so it changes it's elastic potential energy to kinetic energy.
Answer:
The angular speed after 6s is 
.
Explanation:
The equation
relates the moment of inertia 
of a rigid body, and its angular acceleration 
, with the force applied 
at a distance 
from the axis of rotation.
In our case, the force applied is 
, at a distance 
, to a ring with the moment of inertia of 
; therefore, the angular acceleration is
Therefore, the angular speed 
which is
after 6 seconds is
