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NNADVOKAT [17]
3 years ago
5

Suppose a 20-foot ladder is leaning against a building, reaching to the bottom of a second-floor window 15 feet above the ground

. What angle, in radians, does the ladder make with the ground Round your answer to two decimal places
Physics
1 answer:
Papessa [141]3 years ago
7 0

Answer:

The answer is β=0,85 rads

Explanation:

As the ladder is leaning against the building, we can imagine there´s a triangle where 20ft is the hypotenuse and 15ft is the maximum vertical distance between the ladder and the ground, it means, the leg opposite to β which is the angle we need

Let β(betha) be the angle between the ladder and the ground

We also know that sin(betha)=(leg opposite)/(hypotenuse)

In this case we will need to find β, this way:

betha=sin^-1((15ft/20ft))

Then β=48,6°  

We also have that 2πrads is equal to 360°, in this way we find how much β is in radians:

betha=(48,6°)*(2pirads/360°)

then we find β=0,85rads

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A 500-n parachutist opens his chute and experiences an air resistance force of 800 n. the net force on the parachutist is then
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Force of 500 N is acting on the parachutist.

Parachutist applies 500 N force in downward direction.

Answer:

300 N upward

Solution:

Parachutist feels air resistance of 800 N.

Thus, 800 N of force is acting in upward direction.

Total force acting on the parachutist is given by,

F_{net} = air resistance force - force of parachutist

F_{net} = 800-500

F_{net} = 300 N

Direction of force is in upward direction because the air resistance force is more than force of parachutist.

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3 years ago
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The magnitude of the electric current is directly proportional to the _____ of the electric field.
Sedbober [7]
Is proportional to the CHANGE.

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An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large o
Alekssandra [29.7K]

Answer:

0.53m/s^2

Explanation:

We are given that

Mass of wire=m=3.6 g=3.6\times 10^{-3} kg

1 kg=1000 g

Length of wire=l=1.6 m

Mass of object=m'=3 kg

Time,t=60.1 ms=60.1\times 10^{-3} s

1 ms=10^{-3} s

Speed,v=\frac{distance}{time}=\frac{1.6}{60.1\times 10^{-3}}=26.62 m/s

g=\frac{v^2m}{m'l}

Using the formula

g=\frac{(26.62)^2\times 3.6\times 10^{-3}}{3\times 1.6}=0.53m/s^2

8 0
3 years ago
The area around a charged object that can exert a force on other charged objects is an electric ___
Ymorist [56]
Answer is:

Electric field.
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The inner conductor of a coaxial cable has a radius of 0.800 mm, and the outer conductor’s inside radius is 3.00 mm. The space b
ZanzabumX [31]

Answer:

The maximum potential difference is 186.02 x 10¹⁵ V

Explanation:

formula for calculating maximum potential difference

V = \frac{2K_e \lambda}{k}ln(\frac{b}{a})

where;

Ke is coulomb's constant = 8.99 x 10⁹ Nm²/c²

k is the dielectric constant = 2.3

b is the outer radius of the conductor = 3 mm

a is the inner radius of the conductor = 0.8 mm

λ is the linear charge density = 18 x 10⁶ V/m

Substitute in these values in the above equation;

V = \frac{2K_e \lambda}{k}ln(\frac{b}{a}) =  \frac{2*8.99*10^9*18*10^6 }{2.3}ln(\frac{3}{0.8}) =140.71 *10^{15} *1.322 \\\\V= 186.02 *10^{15} \ V

Therefore, the maximum potential difference this cable can withstand is 186.02 x 10¹⁵ V

8 0
3 years ago
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