<h2>Which source would be most reliable for gathering experimental results related to a new compound’s molecular mass : A textbook that lists molecular masses of similar compounds</h2>

Explanation:

Atom:

It is a smallest particle of an element which may as may not have independent existence.

The are very small in size.

Their size is measured in unit nm (nanometer)

1nm – 10⁻⁹ m.

hydrogen atom is smallest of all size is only 10⁻¹⁰ nm

Atoms are represented by symbols (given by berzelius )

Atomic mass of element-

Active atomic mass of atom can’t be measured but relative atomic mass can be known.

I.e. relative atomic mass of an atom of element is defined as average relative mass of atom as compared with atom of 612c taken as 12u.

Atomic mass – no. Of times one atom of he element is heavier then 1/12th of c atom.

Molecule

It is smallest particle of an element or compound which is able to exist independently.

Some element exist as

Diatomic molecuel  eq:- O₂

Triatomic molecule  eq:- O₃

So,

Atomicity – is no. of atoms in a molecule of an element.

Some more examples:- phosphorous P4 (tetra atomic)

sulphur S8 (poly-atomic)

nitrogen N2 (diatomic)

Molecular mass

It is the mass of molecule that is obtained by adding masses of atoms multiplied with number of atoms of each type .

7 0

4 years ago

A 1.1 kg block of iron at 38 ∘C is rapidly heated by a torch such that 13 kJ is transferred to it. What temperature would the bl

AfilCa [17]

Answer:- Iron block final temperature is 64 degree C and copper block final temperature is 76 degree C.

Solution:- These problems are based on the formula:

$q=mC_s\Delta T$

where, q is the heat energy, m is mass, $C_s$ is specific heat and $\Delta T$ is the change in temperature.

mass of iron is given as 1.1 kg. We need to convert it to grams:

$1.1kg(\frac{1000g}{1kg})$ = 1100 g

q is 13 kJ, let's convert it to J:

$13kJ(\frac{1000J}{1kJ})$ = 13000 J

$C_s$ of iron is $\frac{0.450J}{g.^0C}$

Let's calculate change in temperature for iron.

$\Delta T=\frac{13000J}{1100g*\frac{0.450J}{g.^0C}}$

$\Delta T=26 ^0C$

Since, $\Delta T$ = final temperature - initial temperature

26 = final temperature - 38

final temperature = 26 + 38 = 64 degree C

So, The final temperature of iron block would be 64 degree C.

Let's do the same calculations for copper block, it's mass is 890 g and specific heat is $\frac{0.385J}{g.^0C}$ .

$\Delta T=\frac{13000J}{890g*\frac{0.385J}{g.^0C}}$

$\Delta T=38 ^0C$

Now, calculations for final temperature:

$\Delta T$ = final temperature - initial temperature

38 = final temperature - 38

final temperature = 38 + 38 = 76 degree C

So, the final temperature of copper block is 76 degree C.

5 0

3 years ago

element x is a neutral element and has 39 protons. what element is it and how many electrons does it have? (use the periodic tab

alisha [4.7K]

The element itself is Yttrium, which is a transition metal and not that reactive. Since it has 39 protons it will also have 39 electrons.

4 0

3 years ago