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HACTEHA [7]
3 years ago
15

What does amoeba use to move and ingest prey?

Chemistry
1 answer:
melomori [17]3 years ago
7 0
The cytoplasm slides and forms a pseudopodium in front to move the cell forwards. 
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Naturally occurring silicon has an atomic mass of 28.086 and consists of three isotopes. The major isotope is 28Si, natural abun
Elden [556K]

Answer:

29Si has a natural abundance of 4.68%.

30Si has a relative atomic mass of 29.99288 and a natural abundance of 3.09%.

Explanation:

The atomic mass of silicon is given by:

Si=Si²⁸×A₁+Si²⁹×A₂+Si³⁰×A₃

Where:

Si: atomic mass of silicon (28.086)

Si²⁸: relative atomic mass of 28Si (27.97693)

A₁: natural abundance of 28Si (92.23%)

Si²⁹: relative atomic mass of 29Si (28.97649)

A₂: natural abundance of 29Si

Si³⁰: relative atomic mass of 30Si

A₃: natural abundance of 30Si

We also know that 30Si natural abundance is in the ratio of 0.6592 to that of 29Si.

We have to set up a system of three equations in three unknowns:

Si=Si²⁸×A₁+Si²⁹×A₂+Si³⁰×A₃

A₃=0.6592×A₂

A₁+A₂+A₃=1

First, we find substitute the value of A₃ in the third equation and solv teh value of A₂:

A₁+A₂+0.6592×A₂=1

A₁+1.6592×A₂=1

1.6592×A₂=1-A₁

A₂=\frac{1-A₁}{1.6592}=\frac{1-0.9223}{1.6592}=0.0468

Then, we find the value of A₃:

A₃=0.6592×A₂

A₃=0.6592×0.0468=0.0309

Finally, we find the value of Si³⁰ in the first equation:

Si=Si²⁸×A₁+Si²⁹×A₂+Si³⁰×A₃

28.086=27.97693×0.9223+28.97649×0.0468+Si³⁰×0.0309

28.086=27.15922+Si³⁰×0.0309

28.086-27.15922=Si³⁰×0.0309

\frac{0.92678}{0.0309}=Si³⁰

Si³⁰=29.99288

8 0
3 years ago
Why is it useful to know the background level of extinction?
lawyer [7]

Answer:

NOAA and FWS are required by law to compare background rates to current rates.

Explanation:

5 0
3 years ago
When water vapor condenses high in the sky what is formed
Goryan [66]
A cloud is formed because the water vapor gathers in groups
3 0
3 years ago
How much mass does 1 mol of O2 gas have?
cluponka [151]

Answer: 15.99 x2g

Explanation:

8 0
3 years ago
How much heat energy is required to melt 75g of ice at 0°C?
Mnenie [13.5K]

The enthalpy change for melting ice is called the entlaphy of fusion. Its value is 6.02 kj/mol. This means for every mole of ice we melt we must apply 6.02 kj of heat. We can calculate the heat needed with the following equation:

Q = N x ΔH

where:

Q  = heat

N  = moles  

ΔH  = enthalpy

In this problem we would like to calculate the heat needed to melt 35 grams of ice at 0 °C. This problem can be broken into three steps:


1. Calculate moles of water

2. multiply by the enthalpy of fusion

3. Convert kJ to J.


Step 1 : Calculate moles of water

[ 75g ] x (\frac{1 mol}{18.02g} ) =

Step 2 : Multiply by enthalpy of fusion

Q = N × ΔH  = <em> [ Step 1 Answer ]</em> ×  6.02 =

Step 3 : Convert kJ to J

[ Step 2 Answer ] x (\frac{1000j}{1kJ} ) =

Finally rounding to 2 sig figs (since 34°C has two sig figs) we get


Q Would Equal ____

4 0
3 years ago
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