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HACTEHA [7]
3 years ago
15

What does amoeba use to move and ingest prey?

Chemistry
1 answer:
melomori [17]3 years ago
7 0
The cytoplasm slides and forms a pseudopodium in front to move the cell forwards. 
You might be interested in
Calculate the maximum numbers of moles and grams of iodic acid (HIO₃) that can form when 635 g of iodine trichloride reacts with
poizon [28]

What is Chemical Reaction?

A chemical reaction occurs when a certain group of molecules converts into another form without affecting their nuclei; only the transfer or sharing of electrons and the building and breaking of bonds occur.

Main Content

Known :

\mathrm{ICl}_{3}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{ICl}+\mathrm{HIO}_{3}+\mathrm{HCl}

Mass of ICI_3 = 635g

Mass of H_2O = 118.5g

Calculations :

First, balance the given chemical equation by place 2,3 and 5 as the coefficients of ICI_3, H_2O and HCl,\\ Respectively

2 \mathrm{ICl}_{3}+3 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{ICl}+\mathrm{HIO}_{3}+5 \mathrm{HCl}

We multiply the given mass of ICl_3 by the reciprocal of its molar mass to get the number of moles. The molar mass of ICl_3 is 233.26g/mol

\text { Moles of } \mathrm{ICl}_{3}=635 \mathrm{~g} \mathrm{ICl}_{3} \times \frac{1 \mathrm{~mol} \mathrm{ICl}_{3}}{233.26 \mathrm{~g} \mathrm{ICl}_{3}}=2.7223 \mathrm{~mol}  \mathrm{ICl}_{3}

Them, we multiply the ratio between ICl_3 and HIO_3. based on the chemical equation, the molar ratio 1 mol HIO_3/2  mol ICl_3.

\text { Moles of } \mathrm{HIO}_{3} \text { formed }=2.7223 \mathrm{~mol} \mathrm{ICl}_{3} \times \frac{1 \mathrm{~mol} \mathrm{HIO}_{3}}{2 \mathrm{~mol} \mathrm{ICl}_{3}}=1.3612 \mathrm{~mol} \mathrm{HIO}_{3}

For water, we again multiply the given mass H_2O by the reciprocal of its molar mass to get the number if moles. The molar mass of H_2O is 18.02g/mol

\text { Moles of } \mathrm{H}_{2} \mathrm{O}=118.5 \mathrm{~g} \mathrm{H}_{2} \mathrm{O} \times \frac{1 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}{18.02 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}}=6.5760 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}

Then, we multiply the molar ratio between H2O and HIOs. Based on the chemical equation, the molar ratio is 1 mol HIO_3/3 Mole H_2O

\text { Moles of } \mathrm{HIO}_{3} \text { formed }=6.5760 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O} \times \frac{1 \mathrm{~mol} \mathrm{HIO}_{3}}{3 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}=2.1920 \mathrm{~mol} \mathrm{HIO}_{3}

We can see that the limiting reactant is ICL_3 since the given mass of ICl_3 forms lesser product than water does. Thus , the maximum number of moles of HIO_3 formed is 1.36 mol HIO_3. We now multiply the molar mas of HIO_3 to the calculated number of moles. The molar mass of HIO_3 is 175.91 g/mol.

Mass of HIO_3 formed (Max) =1.3612 \mathrm{~mol} \mathrm{HIO}_{3} \times \frac{175.91 \mathrm{~g} \mathrm{HIO}_{3}}{1 \mathrm{~mol} \mathrm{HIO}}=239 \mathrm{~g} \mathrm{HIO}_{3}

We multiply the number of moles of ICl_3 by the molar ratio between ICl_3 and H_2O which is 3 mol H_2O mol ICl_3 we get the number of moles of H_2O reacted. Then, we multiply the molar mass of water.

Mass of H_2O reacted =2.7223 \mathrm{~mol} \mathrm{ICl} 3 \times \frac{3 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}{2 \mathrm{~mol} \mathrm{ICl}_{3}} \times \frac{18.02 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}

Mass of H_2O reacted = 73.6g H_2O

We subtract the mass of H_2O reacted from the given mass of H_2O.

Mass of H_2O = 118.5 - 73.6g = 44.9g H_2O

To learn more about Chemical Reaction

brainly.com/question/11231920

#SPJ4

3 0
2 years ago
Fluorine is diatomic element. What is the number of molecules in 10 moles<br> of fluorine gas?
sweet-ann [11.9K]
<h2>Answer:</h2>

6 × 10²⁴ molecules F₂

<h2>General Formulas and Concepts:</h2><h3><u>Chemistry</u></h3>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3><u>Math</u></h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h2>Explanation:</h2>

<u>Step 1: Define</u>

10 mol F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />10 \ mol \ F_2(\frac{6.022 \cdot 10^{23} \ molecues \ F_2}{1 \ mol \ F_2} ) = 6.022 × 10²⁴ molecules F₂

<u>Step 4: Check</u>

<em>We are given 1 sig fig. Follow sig fig rules and round.</em>

6.022 × 10²⁴ molecules F₂ ≈ 6 × 10²⁴ molecules F₂

5 0
3 years ago
Read 2 more answers
Explain The Law of Conservation of Mass​
gayaneshka [121]

Answer:

The Law of Conservation of Mass dates from Antoine Lavoisier's 1789 discovery that mass is neither created nor destroyed in chemical reactions. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.

Hope it's helpful to you

7 0
3 years ago
In each drop-down menu.
larisa86 [58]

Answer:

I might be wrong i'm not sure

Explanation:

Chemical reactions often involve changes in energy due to the breaking and formation of bonds. Reactions in which energy is released are exothermic reactions, while those that take in heat energy are endothermic.

4 0
3 years ago
Which of the following is formed by intense heat and pressure over millions of years?
kumpel [21]

Answer:

B:Metamorphic

Explanation:

Rocks formed under high heat and pressure is essentially the definition of metamorphic rock :)

8 0
3 years ago
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