Answer:
See explanation and image attached
Explanation:
The reaction of (R)-2-chloro-3-methylbutane with potassium tert-butoxide yields a monosubstituted alkene .
Since the base is bulky, the Hoffman product predominates because attack occurs at the less hindered carbon atom to yield the major product as shown.
The alkene reacts with HBr at the secondary carbon atom to yield a carbocation intermediate which is flat and planar. Attack on either face of the carbocation yields a racemic mixture of the (2R) and (2S) products.
Rearrangement of the carbocation to yield a tertiary carbocation gives the 2-bromo-2-methyl butane product as shown in the image attached.
This question is incomplete, the complete question;
A reaction between liquid reactants takes place at 16°C in a sealed, evacuated vessel with a measured volume of 10.0 L . Measurements show that the reaction produced 37.g of dinitrogen monoxide gas.
Calculate the pressure of dinitrogen monoxide gas in the reaction vessel after the reaction. You may ignore the volume of the liquid reactants. Round your answer to 2 significant digits.
Answer:
Explanation:
Given that;
Volume = 10.0 L
Temperature T = 16°C = ( 16 + 273) = 289 K
we know that molar mass of N₂O = 44 g/mol
number number of moles n will be: weight/molar mass = 37/44 = 0.8409 moles
Universal Gas constant R = 0.0821 atm.mol⁻¹.k⁻¹
pressure p = ?
from the ideal gas law
PV = nRT
P = nRT / n
so we substitute
P = (0.8409 mole × 0.0821 atm.mol⁻¹.k⁻¹ × 289 K) / 10.0 l
P = 19.95195 / 10.0
P = 1.9952 atm
Answer:
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