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Sergio [31]
3 years ago
5

How do the particles that are dispersed in a colloid differ from the particles suspended in a suspension?

Chemistry
1 answer:
Fed [463]3 years ago
5 0

Answer:B, the colloid particles are larger.

PLEASE GIVE BRAINLIEST AND WATCH OUT BEHIND YOU

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What acid and what base would you choose to prepare the salt potassium perchlorate (kclo4)?
Nonamiya [84]
HClO₄ + KOH → KClO₄ + H₂O

HClO₄ - perchloric acid
KOH - potassium hydroxide
8 0
3 years ago
Read 2 more answers
How many moles of nitric acid are present in 35.0 ml of a 2.20 M solution?
vodomira [7]

Answer:

There are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution

Explanation:

Molarity of the solution = 2.20 M

Molarity=\frac{number\:of\:moles}{Volume\:of\:Solution\:in\:L}\\\\Number\:of\:moles=Molarity\times(Volume\:of\:Solution\:in\:L)\\\\Volume\:of\:Solution=35\:mL=35\times10^{-3}L\\\\Number\:of\:moles=2.20\times35\times10^{-3}=77\times10^{-3}\:moles\:of\:HNO_{3}

Therefore, there are 77 millimoles of nitric acid present in 35.0 mL of a 2.20 M solution

8 0
3 years ago
ANSWER ASAP thanks
weqwewe [10]

Answer:

Option D: it's ability to lose electrons

Explanation:

Alkali metals are usually discovered in nature. They have highly reactivity at STP conditions (standard temperature and pressure conditions) and easily lose their outermost electron to form positive ions known that have a charge of +1.

Thus, what can determine the extent of reactivity of an alkali metal, is it's ability to lose electrons

5 0
3 years ago
Read 2 more answers
A first-order reaction (A → B) has a half-life of 25 minutes. If the initial concentration of A is 0.900 M, what is the concentr
Oksanka [162]

Answer:

0.6749 M is the concentration of B after 50 minutes.

Explanation:

A → B

Half life of the reaction = t_{1/2}=25 minutes

Rate constant of the reaction = k

For first order reaction, half life and half life are related by:

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{25 min}=0.02772 min^{-1}

Initial concentration of A = [A]_o=0.900 M

Final concentration of A after 50 minutes = [A]=?

t = 50 minute

[A]=[A]_o\times e^{-kt}

[A]=0.900 M\times e^{-0.02772 min^{-1}\times 50 minutes}

[A] = 0.2251 M

The concentration of A after 50 minutes = 0.2251 M

The concentration of B after 50 minutes = 0.900 M - 0.2251 M = 0.6749 M

0.6749 M is the concentration of B after 50 minutes.

7 0
3 years ago
1 kg of water (specific heat = 4184 J/(kg K)) is heated from freezing (0°C) to boiling (100°C). What is the change in thermal en
Andrews [41]

Answer: 1560632 joules

Explanation:

The change in thermal energy (Q) required to heat ice depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = ?

Mass of frozen water (ice) = 1kg

C = 4184 J/(kg K)

Φ = (Final temperature - Initial temperature)

= 100°C - 0°C = 100°C

Convert 100°C to Kelvin

(100°C + 273) = 373K

Then, Q = MCΦ

Q = 1kg x 4184 J/(kg K) x 373K

Q = 1560632 joules

Thus, the change in thermal energy is 1560632 joules

5 0
3 years ago
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