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vlada-n [284]
3 years ago
5

What color of light is transmitted and refracted by a prism first?

Chemistry
2 answers:
lawyer [7]3 years ago
5 0

Answer:

Explanation:

As the light leaves the prism it is refracted away from the normal. However, the different colours which constitute the white light are not refracted by the same amount. The red light is refracted least. The violet light is refracted most.

nevsk [136]3 years ago
3 0

Answer:

The red light is refracted least. The violet light is refracted most.

Explanation:

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¿Puede ocurrir una reacción química sin generar cambios visibles?
Mrac [35]

Answer:

si

Explanation:

6 0
3 years ago
Which of the following represents positron emission? Select one: a. 3015P ---> 3014Si + ___ b. 23892U ---> 23490Th + ___ c
xxTIMURxx [149]
The simple trick which one can consider in such problem where it is asked for positron emission is :
<span>When the atomic number goes DOWN by one and mass number remains unchanged, then a positron is emitted.
</span>
<span>a.  </span>P^{30}_{15}  ----\ \textgreater \   Si^{30}_{14} + e^{0}_{1}^+
<span>
Here the atomic number decreases by one.

Similarly, options b and d are eliminated.

Option c is also not the answer.
For c, Count the atomic number on left side and compare it with right side. You will see it is 9 on left and 8 on right. Atomic no. did go down by 1. But the atomic mass is changed as well.

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8 0
3 years ago
Which of the mole ratios would be used to set up the below problem?
san4es73 [151]
A.3 moles H2

1 mole N2

I think it is correct
4 0
3 years ago
Which of the following best describes technology
kotegsom [21]

were are the choices

5 0
2 years ago
Read 2 more answers
The half life of 226/88 Ra is 1620 years. How much of a 12 g sample of 226/88 Ra will be left after 8 half lives?
Aloiza [94]

Answer:

0.0468 g.

Explanation:

  • The decay of radioactive elements obeys first-order kinetics.
  • For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).

Where, k is the rate constant of the reaction.

t1/2 is the half-life time of the reaction (t1/2 = 1620 years).

∴ k = ln2/(t1/2) = 0.693/(1620 years) = 4.28 x 10⁻⁴ year⁻¹.

  • For first-order reaction: <em>kt = lna/(a-x).</em>

where, k is the rate constant of the reaction (k = 4.28 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = t1/2 x 8 = 1620 years x 8 = 12960 year).

a is the initial concentration (a = 12.0 g).

(a-x) is the remaining concentration.

∴ kt = lna/(a-x)

(4.28 x 10⁻⁴ year⁻¹)(12960 year) = ln(12)/(a-x).

5.54688 = ln(12)/(a-x).

Taking e for the both sides:

256.34 = (12)/(a-x).

<em>∴ (a-x) = 12/256.34 = 0.0468 g.</em>

8 0
3 years ago
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