False They can function as both. An example is Aluminium Oxide. These kind of substances are called "Amphoteric", they can behave as both acids and bases.
Answer:
The temperature of the methanol will increase more rapidly.
Explanation:
The premise of your question is incorrect. Methanol has an OH group, so there ARE hydrogen bonds among methanol molecules.
However, the specific heat capacity of methanol is 2.53 J°C⁻¹g⁻¹, while that of water is 4.18 J°C⁻¹g⁻¹.
Thus, it takes 65 % more heat energy to raise the temperature of a given mass of water by 1 °C than it does to raise the temperature of an equal mass of methanol by the same amount.
The two samples are receiving heat energy at the same rate, so the methanol will heat up faster than the water.
Ethene react with oxygen at a 
molar ratio:
Convert the quantity of each reactant supplied to number of moles of particles:
The question stated not whether both reactants were used up in this process. Thus start by testing the assumption that e.g., ethene was used up while some oxygen gas were left unreacted (ethene as the <em>limiting </em>reagent.) Under this assumption, the relative availability of the two species, 
and 
(as seen in the balanced chemical equation) shall satisfy the relationship
In other words,
Evaluating the expression 
with data given in the question yields approximately 
, which does satisfy the relationship. Hence the assumption holds and ethene is the limiting reactant.
The quantity of a reactant produced in a chemical reaction is related to its stoichiometric (of relating to proportions) relationship with the limiting reactant (or any of the reactants in case of more than one limiting reactant.) For this scenario, given the molar ratio 
,
Hydrogen peroxide decomposes to yield water and oxygen gas
That is; H2O2 (l) = H2O (l) + O2(g)
The standard heat of formation; H2O2 (l) = -187.6 kJ/mol; H2O(l) = -285.8 kJ/mol
1 mole of hydrogen peroxide contains 34 g
Thus, 5.4 g contains 5.4/34 = 0.1588 moles
The moles of water produced will also be equivalent to 0.1588 moles
Heat = heat of formation of product - reactant
Therefore; Heat = (0.1588 moles × -285,8 )- (0.1588× -187.6)
= -15.594 kJ
Group 1A (the alkali metals) almost always form cations (positive ions). They'd need anions (negative ions) to ionic bond with. Beryllium (Be) is group 1A already and forms Be+ cation. Bromine is a halogen, and forms Br-, an anion. Platinum is a metal, and usually won't ionic bond with anything. Francium is rare and highly radioactive, plus it so happens to be group 1A as well. Only bromine can form the anion that the group 1A cations need.
