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soldi70 [24.7K]
3 years ago
11

Which of the following elements is most likely to form an ion that will then form an ionic bond with an ion of a Group 1A elemen

t?
a. Be
b. Br
c. Pt
d. Fr
Chemistry
1 answer:
solniwko [45]3 years ago
3 0
Group 1A (the alkali metals) almost always form cations (positive ions). They'd need anions (negative ions) to ionic bond with. Beryllium (Be) is group 1A already and forms Be+ cation. Bromine is a halogen, and forms Br-, an anion. Platinum is a metal, and usually won't ionic bond with anything. Francium is rare and highly radioactive, plus it so happens to be group 1A as well. Only bromine can form the anion that the group 1A cations need.
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horrorfan [7]

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Explanation:

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This means that 12.5/2=<u>6.25 mol</u> of oxygen gas is needed.

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7 0
3 years ago
Xenon gas measure pd to start sith s volume of 15.5kL. If the the volume changes to the 0?6kL and the pressure becomes 44 Pa, wh
Lynna [10]

Answer:

17.03Pa

Explanation:

Given parameters:

Initial volume  = 15.5kL

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Final pressure  = 44Pa

Unknown:

Original pressure = ?

Solution:

The parameters given shows pressure and volume relationship of the given gas. One of the gas laws that predicts pressure - volume relationships is the Boyle's law.

Boyle's law states that "the volume of a fixed mass of gas varies inversely as the pressure changes, if the temperature is constant".

Mathematically,  

             P₁V₁   = P₂V₂

where P₁ is the initial pressure

           V₁ is the initial volume

           P₂ is the final pressure

           V₂ is the final volume

Input the variables and solve for P₁;

               P₁ x 15.5  = 44 x 6

                      P₁  = 17.03Pa

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4 years ago
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Phoenix [80]

Hi There

Explanation:

<u><em>Using the balanced combustion equation you have written, it can be seen that for every mole of methane burned, one mole of carbon dioxide is produced. Thus, if 150 moles of carbon dioxide are produced, 150 moles of methane are being used.  </em></u>

<u><em> </em></u>

<u><em>Now, we need to convert that to grams. Using the molecular weight of methane as 16.0425 g/mol:  </em></u>

<u><em> </em></u>

<u><em>(16.0425 g/mol) * (150 mol) = 2,406.375 grams of methane</em></u>

<u><em>Please mark as brainliest</em></u>

5 0
3 years ago
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