Answer: 6.25 mol
Explanation:
From the reaction that produces water from its elements (shown in the image), we know that for every mole of oxygen gas consumed, 2 moles of water are produced.
This means that 12.5/2=<u>6.25 mol</u> of oxygen gas is needed.
I don't know exactly what you are learning, but i know that chemistry involves the practice of mixing chemicals together to see what kind of reaction they make, if they make a reaction at all.
Answer:
17.03Pa
Explanation:
Given parameters:
Initial volume = 15.5kL
Final volume = 6kL
Final pressure = 44Pa
Unknown:
Original pressure = ?
Solution:
The parameters given shows pressure and volume relationship of the given gas. One of the gas laws that predicts pressure - volume relationships is the Boyle's law.
Boyle's law states that "the volume of a fixed mass of gas varies inversely as the pressure changes, if the temperature is constant".
Mathematically,
P₁V₁ = P₂V₂
where P₁ is the initial pressure
V₁ is the initial volume
P₂ is the final pressure
V₂ is the final volume
Input the variables and solve for P₁;
P₁ x 15.5 = 44 x 6
P₁ = 17.03Pa
Hi There
Explanation:
<u><em>Using the balanced combustion equation you have written, it can be seen that for every mole of methane burned, one mole of carbon dioxide is produced. Thus, if 150 moles of carbon dioxide are produced, 150 moles of methane are being used. </em></u>
<u><em>
</em></u>
<u><em>Now, we need to convert that to grams. Using the molecular weight of methane as 16.0425 g/mol: </em></u>
<u><em>
</em></u>
<u><em>(16.0425 g/mol) * (150 mol) = 2,406.375 grams of methane</em></u>
<u><em>Please mark as brainliest</em></u>