All categories

3 years ago

Draw a picture of the moon and sun illustrating the full moon phrase

Chemistry

2 answers:

jek_recluse [69]3 years ago

6 0

Hi Sydney!

I can't draw in this question, but there is a picture showing this phase for you to follow when you draw it.

Hope This Helps :)

BaLLatris [955]3 years ago

3 0

for your question I found a picture since I have no time to draw

right now but here

You might be interested in

Trimix 10/50 is a gas mixture that contians 10% oxygen and 50% helium, and the rest is nitrogen. If a tank of trimix 10/50 has a

Marat540 [252]

Answer : The partial pressure of helium is, $1.815\times 10^4KPa$

Solution : Given,

Molar mass of $O_2$ = 32 g/mole

Molar mass of helium = 4 g/mole

Molar mass of $N_2$ = 28 g/mole

Total pressure of gas = $2.07\times 10^4KPa$

As we are given gases in percent, that means 10 g of oxygen gas, 50 g of helium gas and 40 g of nitrogen gas present in 100 g of mixture.

First we have to calculate the moles of oxygen, helium and nitrogen gas.

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{10g}{32g/mole}=0.3125moles$

$\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{50g}{4g/mole}=12.5moles$

$\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{40g}{28g/mole}=1.428moles$

Now we have to calculate the total number of moles of gas mixture.

$\text{Total number of moles of gas}=\text{Moles of oxygen gas}+\text{Mole of helium gas}+\text{Moles of nitrogen gas}$

$\text{Total number of moles of gas}=0.3125+12.5+1.428=14.24moles$

Now we have to calculate the moles fraction of helium gas.

$\text{Mole fraction of He gas}=\frac{\text{Moles of He gas}}{\text{Total number of moles of gas}}=\frac{12.5}{14.25}=0.877$

Now we have to calculate the partial pressure of helium.

$p_{He}=X_{He}\times P_T$

where,

$p_{He}$ = partial pressure of helium

$P_T$ = total pressure

$X_{He}$ = mole fraction of helium

Now put all the given values in this formula, we get

$p_{He}=(0.877)\times (2.07\times 10^4KPa)=1.815\times 10^4KPa$

Therefore, the partial pressure of helium is, $1.815\times 10^4KPa$

8 0

3 years ago

In an experiment magnesium ribbon was heated in air. The product was found to be heavier than the original ribbon. Potassium man

KatRina [158]

Burning a magnesium ribbon in the air is an addition reaction while heating potassium manganate 7 is a decomposition reaction.

<h3>Addition and decomposition reactions</h3>

Magnesium burns in air to produce magnesium oxide as follows:

$2Mg + O_2 --- > 2MgO$

Potassium manganate 7 burns to produce multiple products as follows:

$2 KMnO_4 --- > K_2MnO_4 + MnO_2(s) + O_2$

Thus, the MgO will be heavier than Mg. On the other hand, $MnO_2$ will be less heavy than $KMnO_4$ .

More on reactions can be found here: brainly.com/question/17434463

#SPJ1

7 0

1 year ago

A new grill has a mass of 30.0 kg. you put 1.5 kg of charcoal in the grill. you burn all the charcoal and the grill has a mass o

atroni [7]

The reaction for burning of charcoal or complete combustion is as follows:

$C(s)+O_{2}(g)\rightarrow CO_{2}(g)$

From the above balanced reaction, 1 mole of carbon releases 1 mole of $CO_{2}$ gas.

Converting mass of charcoal into moles as follows:

$n=\frac{m}{M}$

Molar mass of pure carbon is 12 g/mol thus,

$n=\frac{1.5\times 10^{3} g}{12 g/mol}=125mol$

The same moles of $CO_{2}$ is released. Converting these moles into mass as follows:

m=n×M

Molar mass of $CO_{2}$ is 44 g/mol thus,

$m=125mol\times 44 g/mol=5.5\times 10^{3}g$

Converting mass into kg,

$1g=10^{-3}kg$

Thus, total mass of gas released is 5.5 kg.

7 0

3 years ago

Which pair consists of a molecular formula and its corresponding empirical formula?

MissTica

<span>3) P4O10 and P2O5
The mass of the P4O10 divided by the mass of the P2O5=2, and if you multiply the number of atoms in the P2O5 by 2, you get the P4O10, thus P2O5 is its empirical formula.</span>

3 0

3 years ago

Read 2 more answers

How many half lives would pass if a mass of copper-66 decayed for 51 minutes? The half life of Cu-66 is 5.10 minutes.

Sveta_85 [38]

Divide 51 by 5.1, it's 10 half lives

4 0

3 years ago