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2 years ago

Which statement best describes the role of oxygen in cellular respiration?

Chemistry

1 answer:

Genrish500 [490]2 years ago

6 0

The role of oxygen in cellular respiration is to make water molecules. hence, option (D) is correct.

<h3>What is Cellular respiration ?</h3>

Cellular respiration is the process in which cells break down molecules for energy.

The cells use oxygen to break down food in the form of glucose to produce water and release carbon dioxide.

During aerobic cellular respiration, glucose reacts with oxygen, forming ATP that can be used by the cell. Carbon dioxide and water are created as byproducts.

In this reaction, energy is produced in the form of ATP that is used by the cell for its various activities.

Thus the correct answer is option D.

Learn more about respiration here ;

brainly.com/question/12605249

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When 0.42 g of a compound containing C, H, and O is burned completely, the products are 1.03 g CO2 and 0.14 g H2O. The molecular

Luda [366]

<u>Answer:</u> The empirical and molecular formula for the given organic compound is $C_2H_2O_4$ and $C_6H_4O_2$

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=1.03g$

Mass of $H_2O=0.14g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 1.03 g of carbon dioxide, $\frac{12}{44}\times 1.03=0.28g$ of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.14 g of water, $\frac{2}{18}\times 0.14=0.016g$ of hydrogen will be contained.

Mass of oxygen in the compound = (0.42) - (0.28 + 0.016) = 0.124 g

To formulate the empirical formula, we need to follow some steps:

<u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.28g}{12g/mole}=0.023moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.016g}{1g/mole}=0.016moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.124g}{16g/mole}=0.00775moles$

<u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00775 moles.

For Carbon = $\frac{0.023}{0.00775}=2.96\approx 3$

For Hydrogen = $\frac{0.016}{0.00775}=2.06\approx 2$

For Oxygen = $\frac{0.00775}{0.00775}=1$

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 2 : 1

Hence, the empirical formula for the given compound is $C_3H_{2}O_1=C_3H_2O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

We are given:

Mass of molecular formula = 108.10 g/mol

Mass of empirical formula = 54 g/mol

Putting values in above equation, we get:

$n=\frac{108.10g/mol}{54g/mol}=2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(3\times 2)}H_{(2\times 2)}O_{(1\times 2)}=C_6H_4O_2$

Thus, the empirical and molecular formula for the given organic compound is $C_3H_2O$ and $C_6H_4O_2$

6 0

3 years ago

If the volume of a cylinder is reduced from 8.0 liters to 4.0 liters, the pressure of the gas in the cylinder will change from 7

Elza [17]

Answer:

P₂ = 140 KPa

Explanation:

Given data:

Initial volume = 8.0 L

Final volume = 4.0 L

Initial pressure = 70 KPa

Final pressure = ?

Solution:

According to Boyle's law

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 70 KPa ×8.0 L/4.0 L

P₂ = 560 KPa .L / 4.0 L

P₂ = 140 KPa

6 0

3 years ago

Which process results in a chemical change?

Alla [95]

D) burning magnesium ribbon, as combustion is a chemical reaction so causes chemical change. The other 3 options do not involve reactions so there isn't a chemical change.

5 0

3 years ago

Read 2 more answers

A person walking covers 5.20 m in 10.4 s. How fast is the person moving?

salantis [7]

Answer:

Explanation:

Velocity = distance over time

where distance = 5.20 m

time = 10.4 s.

velocity = <u> 5.20 m </u>

10.4 s.

= 0.50 m/s

8 0

2 years ago

Which observation could you make based on stimuli to your photoreceptors?(1 point)

Montano1993 [528]

Answer:

last one which is d

Explanation:

thankskd

6 0

3 years ago