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Verdich [7]
3 years ago
15

Your answer should contain numbers and l's b what value of l minimizes the volume in part a.?

Chemistry
1 answer:
Katyanochek1 [597]3 years ago
3 0
Need more details of the question. What was in part a?
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A 50.0 mL sample of an aqueous H2SO4 solution is titrated with a 0.375 M NaOH solution. The equivalence point is reached with 62
vesna_86 [32]

Answer: The concentration of H_2SO_4 is 0.234 M

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity H_2SO_4 = 2

M_1 = molarity of H_2SO_4 solution = ?

V_1 = volume of  H_2SO_4 solution = 50.0 ml

n_2 = acidity of NaOH = 1

M_1 = molarity of NaOH solution = 0.375 M

V_1 = volume of  NaOH solution = 62.5 ml

Putting in the values we get:

2\times M_1\times 50.0=1\times 0.375\times 62.5

M_1=0.234M

Therefore concentration of H_2SO_4 is 0.234 M

6 0
2 years ago
Color , texture , and odor are all _______ of matter .
frosja888 [35]
Property of matter, I think.
7 0
3 years ago
Read 2 more answers
Give three examples of environmental, industrial and bio-chemistry.
JulsSmile [24]

Three examples of environmental, industrial and bio-chemistry are listed below:

  • Environmental chemistry: Contamination, Atmospheric Deposition, and Soil Pollution.
  • industrial chemistry:  industrial inorganic chemicals, industrial organic chemicals, and agricultural chemicals
  • bio-chemistry: genetic, immunology, and enzymology

<h3>Meaning of Chemistry</h3>

Chemistry can be defined as a branch of science which is concerned with the substances matter is composed of, their properties and reactions,

Chemistry also deals with the use of such reactions to form new substances.

In conclusion, Three examples of environmental, industrial and bio-chemistry are listed anove

Learn more about chemistry: brainly.com/question/24419453

#SPJ1

4 0
2 years ago
I need help with question 2 I will brainliest you if I’m able to
erik [133]

Answer:

Blank 1: Microscope

Blank 2: Cells

4 0
2 years ago
Read 2 more answers
In a percentage composition investigation a compound was decomposed into its elements: 20.0 g of calcium, 6.0 g of carbon, and 2
inysia [295]

The percentage composition of this compound : 40%Ca, 12%C and 48%O

<h3>Further explanation</h3>

Given

20.0 g of calcium,

6.0 g of carbon,

and 24.0 g of oxygen.

Required

The percentage composition

Solution

Total mass of compound :

=mass calcium + mass carbon + mass oxygen

=20 g + 6 g + 24 g

=50 g

Percentage composition :

  • Ca-calcium

\tt \dfrac{20}{50}\times 100\%=40\%

  • C-carbon

\tt \dfrac{6}{50}\times 100\%=12\%

  • O-oxygen

\tt \dfrac{24}{50}\times 100\%=48\%

3 0
2 years ago
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