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2 years ago

Phosphorus and fluorine form a covalent compound, phosphorus trifluoride.

Chemistry

1 answer:

Nesterboy [21]2 years ago

8 0

Answer:

Valence electrons

Explanation:

The formation of phosphorus trifluoride is orchestrated by the sharing of the valence electrons between phosphorus and fluorine.

This is called covalent bonding. In covalent bonding, elements with zero or very small electronegativity combines together. Such bonding occurs between non-metals.

For this bond to form, phosphorous shares its 5 electrons with the 3 of the fluorine.

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Phosphorus react with carbon<br>

ZanzabumX [31]

Answer:

Phosphorus atoms can bond with oxygen atoms to form ester groups. These can bond with carbon atoms, yielding a large number of organic phosphorus chemicals. These are found in many important biological processes

6 0

3 years ago

A gas has a pressure of 8.5atm and occupies 24L at 25∘C. What volume (in liters) will the gas occupy if the pressure is increase

Vesna [10]

The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L

From the question given above, the following data were obtained:

Initial pressure (P₁) = 8.5 atm

Initial volume (V₁) = 24 L

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Final pressure (P₂) = 13.5 atm

Final temperature (T₂) = 15 °C = 15 + 273 = 288 K

<h3>Final volume (V₂) =? </h3>

The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298} = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\$

Cross multiply

298 × 13.5 × V₂ = 204 × 288

4023 × V₂ = 58752

Divide both side by 4023

$V_{2} = \frac{58752}{4023}\\\\$

Therefore, the final volume of the gas is 15 L

Learn more: brainly.com/question/25547148

3 0

2 years ago

what is the ratio of the rate of effusion of helium (atomic mass 4.00 amu) to that of oxygen gas (molecular mass 32.0 amu)?

nignag [31]

Answer:

3 : 1

Explanation:

Let the rate of He be R1

Molar Mass of He (M1) = 4g/mol

Let the rate of O2 be R2

Molar Mass of O2 (M2) = 32g/mol

Recall:

R1/R2 = √(M2/M1)

R1/R2 = √(32/4)

R1/R2 = √8

R1/R2 = 3

The ratio of rate of effusion of Helium to oxygen is 3 : 1

8 0

2 years ago

3. Did pushing (compression), pulling (tension), or sideways forces (shear) in the rock layers produce the folds and faults?

Neko [114]

Pushing(Compression) Causes the faults and folds

3 0

3 years ago

Nitrogen reacts with hydrogen to produce ammonia gas as follows. mc023-1.jpg How many moles of nitrogen would react with excess

anzhelika [568]

The balanced reaction is:

N2 + 3H2 = 2NH3

We are given the amount of the product to be produced.This will be the starting point of our calculations. We use the ideal gas equation to find for the number of moles.

<span>
n = PV / RT = 1.00(.520 L) / (0.08206 atm L/mol K ) 273 K
n= 0.0232 mol NH3

</span>0.0232 mol NH3 (1 mol N2 / 2 mol NH3) = 0.0116 mol N2

<span>Therefore, the correct answer is A.</span>

7 0

2 years ago

Read 2 more answers