I think the answer would be <span>A=0.85
B=(1 - 0.15)d
C=85d
D=0.85d</span>
Answer:
Given :- ABCD is a square.
To proof :- AC = BD and AC ⊥ BD
Proof :- In △ ADB and △ BCA
AD = BC [ Sides of a square are equal ]
∠BAD = ∠ABC [ 90° each ]
AB = BA [ Common side ]
△ADB ≅ △BCA [ SAS congruency rule ]
⇒ AC = BD [ Corresponding parts of congruent triangles are equal ]
In △AOB and △AOD
OB = OD [ Square is also a parallelogram therefore, diagonal of parallelogram bisect each other ]
AB = AD [ Sides of a square are equal ]
AO = AO [ Common side ]
△AOB ≅ △ AOD [ SSS congruency rule ]
⇒ ∠AOB = ∠AOD [ Corresponding parts of congruent triangles are equal]
∠AOB + ∠AOD = 180° [ Linear pair ]
∠ AOB = ∠AOD = 90°
⇒ AO ⊥ BD
⇒ AC ⊥ BD
Hence proved, AC = BD and AC ⊥BD
Answer: 200
Explanation: 348
/ | \
Hundred | \
Tens \
Single
163.89 + 36.11 = 200
163.89 - 63.89 = 100
|
|
What is the lowest number (Not including +/- sign before it)
Answer: 1st one/36.11
<span>Final answer (what you put on paper): 100</span>
Answer:
26 feet
Step-by-step explanation:
Let the length of the required wire =l
The height of the tree =24 cm
We want the tree to fall to the ground 10 feet away from the base.
Ths problem forms a right triangle which I have drawn and attached below.
To determine the length of the wire l required, we use Pythagoras theorem to solve for the hypotenuse of the right triangle.

Thw wire must be 26 feet long to reach the ground.
18 m min 100 cm 30 cm
------ x ----- x --------- = ------
min 60 s m s