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2 years ago

A violin string has a length of 327mm and produces a note of frequency 440Hz.

1 answer:

6 0

The characteristics of the standing wave we can find the backlash for the frequency of the wave when the string is shortened is:

The new frequency is f = 657 Hz

<h3>How is a standing wave produced?</h3>

A standing wave is produced when a traveling wave meets an obstacle and bounces, the sum of the two waves results in a wave that does not propagate in space.

In the event that the obstacle is a fixed point, there is a node at this point. The expression for the length of the standing wave.

L = $\frac{\lambda }{2}$ fundamental frequency

L = $2 \frac{\lambda}{2}$ second harmonic

L = $3 \frac{\lambda}{2}$ third harmonic

L = $n \frac{\lambda}{2}$ general term.

Where L is the length of the chord, lan the wavelength and n an integer.

Wave speed is related to wavelength and frequency.

v = λ f.

Let's substitute.

v = $\frac{2L}{n}$

They indicate that initially the string has a length of L₀ = 327 mm= 0.327m and the frequency is f₀ = 440 Hz.

v n = 2L₀ f₀

v n = 2 0.327 440

v n = 287.76

They indicate that the tension on the string do not changes and the speed of the wave depends only on the tension and the density of the string, therefore it is constant, we assume that the harmonic does not change either, therefore the new length.

v n = 2 L f

Let's substitute.

287.76 = 2 L f

f = $\frac{287.76x}{2L}$

Let's calculate.

f = $\frac{287.76}{2 \ 0.219}$

f = 656.99 Hz

In conclusion with the characteristics of the standing wave we can find the backlash for the frequency of the wave when the string is shortened is:

The new frequency is: f = 657 Hz

Learn more about standing waves here: brainly.com/question/17031219

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A child blows a leaf from rest straight up in the air. The leaf has a constant upward acceleration of magnitude 1.0\,\dfrac{\tex

Novosadov [1.4K]

Answer:

Explanation:

Given

Acceleration a = 1.0m/s²

Displacement S = 1.0m

Required

Time t taken by the leaf to displace

Using the equation of motion

S = ut+1/2at²

Substitute

1.0 = 0+1/2(1)t²

1 = t²/2

Cross multiply

t² = 2

t = ±√2

t = 1.41secs

It takes the leaf to 1.41s to displace by 1m upward

6 0

3 years ago

Okay please help me all my assignments are due tomorrow! I need to know 5 examples of all 6 simple machines that can be found in

iren [92.7K]

Answer:

Inclined Plane – A ramp, for example a wheelchair ramp. Paired inclined planes make a pitched roof.

Wheel & Axle – On lawnmowers and wheelbarrow. Also, found in cabinet door glides and on appliances. Another common example – door knobs and even inside those locksets.

Lever – The bottle opener. Tools – the crowbar, and scissors or pliers. Double Levers – a door, a toilet seat, a broom.

Pulley – Old wood windows, some garage doors, workshop or garage lifting systems.

Wedge – The shim – used throughout the home in construction. For example, when installing doors, windows, cabinets, etc. Sometimes used to level furniture or chairs.

Screw – Like the wedge, above, well, you couldn’t build a house without screws. Certain types of plumbing valves. Plus, a jar lid is a popular example.

Now for deeper look at the simple machines found around our homes.

The hope this will be helpful.

3 0

3 years ago

A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position

irga5000 [103]

(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

<em>Mass of the ball, m = 2.4 kg</em>

<em />

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

$f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz$

The angular frequency of the oscillation is calculated as follows;

$\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s$

The force constant of the spring is calculated as follows;

$\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m$

Learn more about general wave equation here: brainly.com/question/25699025

4 0

3 years ago

What does it mean when work is positive?

Degger [83]

Answer:

To have a positive job, the two vectors must have the same direction

Explanation:

Work is a scalar defined as the scalar product of two vectors, the froce and the displacement. To have a positive job, the two vectors must have

collinear and that their arrows point in the same direction.

You can also appreciate this from the work equation

W = F. r

bold indicate vector

W = F r cos θ

With θ the angle between force and displacement

7 0

3 years ago

A person hangs from a nylon rope (Young's modulus of 5 x 109 N/m2) as seen in the picture below. The rope stretches by 2 % and h

disa [49]

Answer:

959183.7 kg

Explanation:

from the question we have :

young modulus = 5 x 10^{9} N/m^{2}

strain = 2% = 2÷100 = 0.02

diameter = 0.03 m

radius = 0.015 m

acceleration due to gravity (g) = 9.8 m/s^{2}

we can get the mass from the formula below

young modulus = stress ÷ strain

where

stress = \frac[force}{area} = \frac {mass x g}{area}

area = 2πr = 2π x 0.015 = 0.094

therefore

young modulus = \frac{\frac {mass x g}{area}}{strain}

5 x 10^{9} = \frac{\frac {mass x 9.8}{0.094}}{0.02}

mass = \frac{5 x 10^{9} x 0.02 x 0.094}{9.8}

mass = 959183.7 kg

8 0

3 years ago