All categories

3 years ago

Will mark brainliest! How many sodium atoms are there in 26.3 grams of sodium oxide (Na2O)?

Chemistry

1 answer:

SVEN [57.7K]3 years ago

8 0

Answer:

${5.11 * 10^{23} atoms Na}$

Explanation:

${26.3 g} {Na_{2}O}$ * $\frac{1 mol Na_{2}O}{61.979 g Na_{2}O}$ * $\frac{2 mol Na}{1 mol Na_{2}O}$ * $\frac{6.022*10^{23} atoms Na}{1 mol Na}$

= ${5.11 * 10^{23} atoms Na}$

You might be interested in

Specific heat of Fe=0.473 J/g degree C; specific hear of Pb= 0.0305 J/g degree Celcius. To raise the temperature of 1.0 g of the

enot [183]

B. Fe requires more energy than does Pb.

8 0

3 years ago

Draw the Lewis structure for the Se and 2 H atoms.

notsponge [240]

Here is your answer.

5 0

3 years ago

The Ksp of yttrium iodate, Y(IO3)3 , is 1.12×10−10 . Calculate the molar solubility, s , of this compound.

torisob [31]

Answer:

1.427x10^-3mol per L

Explanation:

$Y(IO_{3} )_{3} ---- Y^{3+} +IO_{3} ^{3-}$

I could use ⇌ in the math editor so I used ----

from the question each mole of Y(IO3)3 is dissolved and this is giving us a mole of Y3+ and a mole of IO3^3-

Ksp = [Y^3+][IO3-]^3

So that,

1.12x10^-10 = [S][3S]^3

such that

1.12x10^-10 = 27S^4

the value of s is 0.001427mol per L

= 1.427x10^-3mol per L

so in conclusion

the molar solubility is therefore 1.427x10^-3mol per L

3 0

3 years ago

Name every block in mc

maks197457 [2]

Answer:

Andesite.
Bedrock.
Basalt. Smooth.
Blackstone.
Gilded.
Calcite.
Cobblestone.
Mossy.
Deepslate.
Diorite.

7 0

3 years ago

Read 2 more answers

In the decomposition reaction, 1 mole of water (mw = 18.015 g/mol) was produced for every mole of cuo (mw = 79.545 g/mol) produc

natita [175]

Reactives -> Products

CuO and water are products.

I found this reaction which has CuO and water as products: decomposition of Cu(OH)2.

Cu(OH)2 -> CuO + H2O

Stoichiometry calculus involve the mole proportions you can see in the reaction: When 1 mole of Cu(OH)2 reacts, 1 mole of CuO and 1 mole of H2O are formed.

Considering the molar masses:

Cu(OH)2 = 83.56 g/mol

CuO = 79.545 g/mol

H2O = 18.015 g/mol

Then: When 83.56 g of Cu(OH)2 react, 79.545 g of CuO and 18.015 g H2O are formed.

You should use that numbers in the rule of three:

79.545 g CuO __________18.015 g water

3.327 g CuO__________ x =3.327*18.015 /79.545 g water

x= 0.7535 g water

3 0

3 years ago