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kumpel [21]
3 years ago
9

Which statement is true concerning the Haber Process?

Chemistry
1 answer:
kakasveta [241]3 years ago
4 0

Answer: the answer is B The Haber Process is used in the manufacturing of ammonia from nitrogen and hydrogen, and then goes on to explain the reasons for the conditions used in the process. The process combines nitrogen from the air with hydrogen derived mainly from natural gas (methane) into ammonia.

Explanation: Mark as brainliest if it helped!!

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What happens to the electrons in an ionic bond?
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Answer:

In an ionic bonds, the metal loses electrons to become a positively charged cation, In which the nonmetal accepts those electrons to become a negatively charged anion.

Explanation:

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3 years ago
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Potassium is isotopic and has RAM of 39.5 work out the percentage abundance of each isotope in a given sample of potassium which
Troyanec [42]

Yo sup??

Let the percentage of K-39 be x

then the percentage of K-40 is 100-(x+0.01)

We know that the net weight should be 39.5. Therefore we can say

(39*x+40*(100-(x+0.01))+38*0.01)/100=39.5  

(since we are taking it in percent)

39*x+40*(100-(x+0.01))+38*0.01=3950

39x+4000-40x-0.4+0.38=3950

2x=49.98

x=24.99

=25 (approx)

Therefore K-39 is 25% in nature and K-40 is 75% in nature.

Hope this helps.

3 0
3 years ago
What is the balanced chemical equation for the combustion of sulphur
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Answer:

S+O2⇒SO2

Explanation:

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3 years ago
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What is one interaction between the geosphere and the cryosphere
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The water cycle is one interaction between the geosphere and the cryosphere.
7 0
4 years ago
A solution is created by dissolving 11.0 grams of ammonium chloride in enough water to make 235 mL of solution. How many moles o
Amanda [17]

Answer:

The correct answer is 0.206 moles

Explanation:

According to the given scenario, the calculation of the number of moles of ammonium chloride is available in the resulting solution is given below:

Given that

Amount of NH_4Cl is 11.0 grams

And, the volume is 235 mL

Now the molar mass of NH_4Cl is 53.49g/mol

So, the number of moles presented is

= 11.0 ÷ 53.49

= 0.206 moles

hence, the number of moles of ammonium chloride are available in the resulting solution is 0.206 moles

7 0
3 years ago
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