Answer:
The pressure of CH3OH and HCl will decrease.
The final partial pressure of HCl is 0.350038 atm
Explanation:
Step 1: Data given
Kp = 4.7 x 10^3 at 400K
Pressure of CH3OH = 0.250 atm
Pressure of HCl = 0.600 atm
Volume = 10.00 L
Step 2: The balanced equation
CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)
Step 3: The initial pressure
p(CH3OH) = 0.250atm
p(HCl) = 0.600 atm
p(CH3Cl)= 0 atm
p(H2O) = 0 atm
Step 3: Calculate the pressure at the equilibrium
p(CH3OH) = 0.250 - X atm
p(HCl) = 0.600 - X atm
p(CH3Cl)= X atm
p(H2O) = X atm
Step 4: Calculate Kp
Kp = (pHO * pCH3Cl) / (pCH3* pHCl)
4.7 * 10³ = X² /(0.250-X)(0.600-X)
X = 0.249962
p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm
p(HCl) = 0.600 - 0.249962 = 0.350038 atm
p(CH3Cl)= 0.249962 atm
p(H2O) = 0.249962 atm
Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)
Kp = 4.7 *10³
The pressure of CH3OH and HCl will decrease.
The final partial pressure of HCl is 0.350038 atm
Answer:
a)the ionic radius of phosphorus
Explanation:
phosphorus=2.8.6
for phosphorus to become stable(2.8.8) it gains two electrons thus the ionic radious increases bcz of the gained electrons
Step first:
Since, 78.0 percent
by volume is present in the air which implies there are 78 moles of
present in 100 moles of air.
Now,
Mole fraction of
= 
Mole fraction =
= 0.78
Partial pressure is equal to the multiplication of total pressure and mole fraction.
Partial pressure =
(as 1 atm is atmospheric pressure)
= 0.78 atm.
Step second:
Henry's law constant is calculated by:

where,
is solubility of gas
is partial pressure of gas
is henry's law constant
Substitute the value of solubility and partial pressure to find the value of Henry's law constant in above formula:

k = 
= 
Thus, Henry's Law constant is
.
No, they do not. Hope I helped! :)
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