Answer:
1.28 m
Explanation:
Given;
Radius, r = 1.5 cm = 0.015 m
Time, t = 19 s
Average angular speed = 4.5 rad/s
Consider a point when the tape is moving at a constant velocity along the circumference of the circular reel of radius r. The linear velocity v at this point is given by;
v = rω ----(1)
Where
v is the linear velocity of the circular motion
r is the radius of the reel
ω is the the angular velocity.
At a point the tap undergoes a linear motion before passing round the reel of the cassette. The linear velocity v at this point is given by;
v = L/t ----(2)
where;
v is the velocity of the linear motion
L is the length of the tape (distance covered by the tape)
t is the time taken
Equating equation(1) and equation (2)
L/t = rω
L = rωt
Substituting the given values,
L = 0.015 × 4.5 × 19
L = 1.2825 m
L = 1.28 m
You should rest as much as possible
Answer:
Fs = 32N
Fh = 21 N
Explanation:
Statics
Let Fs be the force of the shoulder, assumed upward
Let Fh be the force of the hand, assumed downward
Sum moments about the hand to zero
1.1(9.8)[67] - Fs[22.5] = 0
Fs = 32N
Sum vertical forces to zero
32 - Fh - 1.1(9.8) = 0
Fh = 21 N
Or we could sum moments about the shoulder point
1.1(9.8)[67 - 22.5] - Fh[22.5] = 0
Fh = 21 N
Answer:
Magnetic field strength required for this is 0.25 T
Explanation:
As we know that the proton moves in circular path in uniform magnetic field
so the radius of the path of the circle is given as
here we know that
now we have
so we have
Sc (21) , Y (39) , La (57) , Ce (58) , Pr (59) , Nd (60) , Pm (61) , Sm (62) , Eu (63) , Gd (64) , Tb (65) , etc (hoped that helped)
