Answer:
Speed of the wave in the string will be 3.2 m/sec
Explanation:
We have given frequency in the string fixed at both ends is 80 Hz
Distance between adjacent antipodes is 20 cm
We know that distance between two adjacent anti nodes is equal to half of the wavelength
So 
We have to find the speed of the wave in the string
Speed is equal to 
So speed of the wave in the string will be 3.2 m/sec
The resultant in the x-direction:
Rx = F1 + F2 = 2.5 N - 1 N = 1.5 N .
The resultant in the y-direction:
Ry = F3 + F4 = 2 N - 3 N = -1 N.
Answer:
Explanation:
As the final Kinetic energy is zero or less than initial kinetic energy, the collision must be inelastic.
In Inelastic collision both the bodies must stick together as final velocity is zero for both the bodies.
To conserve the momentum, momentum associated before the collision of first must be equal and opposite to the momentum associated with the second ball.
i.e.
Answer: The question is incomplete or missing details. here is the remaining part of the question ;
1. impossible to determine
2. half of Isaac’s
3. the same as Isaac’s
4. twice Isaac’s
The angular speed of feng will be the same as that of Isaac. Hence the answer is option 3
Explanation:
Since we have been told that both feng and isaac are riding on a merry go round i.e in a circular motion, irrespective of how fast one ride above the other, the angular speed will be constant since they are riding on a merry go round, as such both feng and isaac will maintain equal angular speed, hence the angular speed of feng will be the same as that of Isaac.
