1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dominik [7]
3 years ago
13

The heating element of a water heater in an apartment building has a maximum power output of 37 kW. Four residents of the buildi

ng take showers at the same time, and each receives heated water at a volume flow rate of 11x10-5 m3/s. If the water going into the heater has a temperature of 14°C, what is the maximum possible temperature of the hot water that each showering resident receives
Physics
1 answer:
kkurt [141]3 years ago
3 0

Answer:

maximum possible temperature is 34.088°C

Explanation:

Given data

power output Q = 37 kW

volume flow rate = 11 x 10^-5 m3/s

temperature t = 14°C

to find out

maximum possible temperature T

solution

we can say

total water volume  = 4 residents  × volume flow

total water volume = 4 × 11 x 10^-5  = 44 × 10^-5 m³/s

so we say total water mass = 1000 × volume

total water mass = 1000 kg/m³ ×  44 × 10^-5  

total water mass = 0.44 kg

we know

dQ/dt = (dm/dt)× (S)× ( T - t)

so here we know specific heat of water S = 4.186 joule/gram °C

37 = 0.44 × 4.186 × (T-14)

T = 34.088°C

maximum possible temperature is 34.088°C

You might be interested in
Please help me with a speech.The topic of my speech is Passion.​
Vikentia [17]

Answer:

Explanation:

Passion

For me, standing on the summit of Mt Everest was the result of following a process. The process of mountaineering. I love mountaineering. I am passionate about it. I love the months of planning for an expedition, the months of sweating and training to prepare my body physically. The meticulous preparation of my equipment. Most of all I love the huge mental challenge I have to overcome before each climb to confront my own fear. All these reasons are why I climb, they are why I climbed Mt Everest and that is why I continue to climb.

Passion is an enormously powerful force. It gives us the strength to get through hard times and setbacks. It gives us strength to overcome our fears, to ignore what other people think of us, to be disciplined and make sacrifices in pursuit of our dreams. Passionate people do not want to take shortcuts – they consider that ‘learning the process’ is an important part of the journey.

In mountaineering it’s easy to spot those who are not passionate about the process. They want to stand on top of the mountain but they are not really interested in the process of climbing the mountain. I feel for these people. Success without hard work is a hollow, empty feeling. They never last long in the sport.

Just as in life, successful mountaineers are the ones who are passionate. They are not there just to stand on the summit. Their passion gives them the energy to work the hardest, fight the longest, and in the words of Winston Churchill “never, never. never give-up”.

3 0
3 years ago
An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi
Veronika [31]

Answer:

s=5.79\ km

\theta=47^{\circ} east of south

Explanation:

Given:

  • distance of the person form the initial position, d'=8.4\ km
  • direction of the person from the initial position, 47^{\circ} north of east
  • distance supposed to travel form the initial position, d=5.3\ km
  • direction supposed to travel from the initial position, due North

<u>Now refer the schematic for visualization of situation:</u>

y=d'.\sin47^{\circ}-d

y=8.4\times \sin47-5.3 ...............(1)

x=d'.\cos47^{\circ}

x=8.4\times \cos47^{\circ} .................(2)

<u>Now the direction of the desired position with respect to south:</u>

\tan\theta=\frac{y}{x}

\tan\theta=\frac{8.4\times \sin47}{8.4\times \cos47}

\theta=47^{\circ} east of south

<u>Now the distance from the current position to the desired position:</u>

s=\sqrt{x^2+y^2}

s=\sqrt{(8.4\times \cos47)^2+(8.4\times \sin47-5.3)^2}

s=5.79\ km

4 0
3 years ago
Pls help i give brainliest
san4es73 [151]

Answer:

a.

Explanation:

cuz whenever the ball was traveling up the staircase it was building up energy to use (potential energy) unlike b.

5 0
3 years ago
Read 2 more answers
work done as mass 1 moves to mass 2. the gravitational force between two point masses separated by a distance r is proportional
pav-90 [236]

Answer:

gravitational force

3 0
3 years ago
6. A wave has a frequency of 600 Hz and is traveling at 300 m/s. What is its<br> wavelength?
Luda [366]

Answer:

0.5m

Explanation:

v=f×lamda

v is 300m/s, f is 600Hz, lamda is ?

lamda=v/f

lamda=300/600

lamda =3/6=1/2m

5 0
3 years ago
Other questions:
  • A force acts on an object and moves it a certain distance
    6·1 answer
  • Gravity is the main force for mass movement.<br> True<br> False
    9·2 answers
  • A ball is thrown horizontally from a cliff at a speed of 10 m/s. you predict that its speed 1 s later will be slightly greater t
    6·2 answers
  • Iron filings were mixed together with salt crystals. What unique property of iron would be BEST to separate the filings from the
    11·2 answers
  • A steel, rigid container is filled with an ideal gas. The gas inside is heated such that its temperature, as measured in kelvin,
    10·1 answer
  • 7. A student walks 3 blocks east, 4 blocks north, and 3 blocks west. What is the displacement of the student? (5 points)
    10·2 answers
  • A horizontal force of 50 N causes a trolley to move a horizontal distance of 30M How much work is done on the trolley by the for
    6·1 answer
  • Prank text my sister, I wanna see her reaction.<br><br> ‪(346) 298-3870‬
    14·1 answer
  • An electron travels 1.49 m in 7.4 µs (microsecWhat is its speed if 1 inch = 0.0254 m? Answer in units of in/min.
    6·1 answer
  • How far from the surface of Earth is the magnitude of Earth's gravitational field equal to 7.86 N/kg?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!