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3 years ago

If the pH is 9, what is the concentration of hydroxide ion? Is this solution

Chemistry

1 answer:

kogti [31]3 years ago

8 0

Answer:

hydrogen peroxide in my place and don't have time And the Base and don't think I will have a clue

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3 years ago

An alpha particle is equivalent to the nucleus of an atom of which element?(1 point)

Monica [59]

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3 years ago

Bilangan oksidasi vanadium paling tinggi terdapat dalam senyawa..

emmasim [6.3K]

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8 0

3 years ago

Please solve for Cu,N,and O an dif you can show how cause ik confused

belka [17]

Cu⇒ 1 atom

N⇒2 atoms

O⇒6 atoms

Total 9 atoms

<h3>Further explanation </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.

A molecular formula is a formula that shows the number of atomic elements that make up a compound.

<em>(empirical formula) n = molecular formula </em>

Chemical formula : Cu(NO₃)₂

Number of Cu : 1

Number of N : 2

Number of O = 2 x 3 = 6

Total atoms in Cu(NO₃)₂ : 1 + 2 + 6 = 9

4 0

2 years ago

What volume in milliliters of 1.420 M sulfuric acid is needed to neutralize 3.209 g of aluminum hydroxide 3 H 2 SO 4 (aq)+2 Al(O

nadya68 [22]

Answer:

$V=43.46mL$

Explanation:

Hello!

In this case, since the reaction between sulfuric acid and aluminum hydroxide is:

$3H_2SO_4+2Al(OH)_3\rightarrow Al_2(SO_4)_3+6H_2O$

Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:

$n_{H_2SO_4}=3.209gAl(OH)_3*\frac{1molAl(OH)_3}{78.00gAl(OH)_3} *\frac{3molH_2SO_4}{2molAl(OH)_3} \\\\n_{H_2SO_4}=0.0617molH_2SO_4$

Then, given the molarity, it is possible to obtain the milliliters as follows:

$V=\frac{n}{M}=\frac{0.0617mol}{1.420mol/L}*\frac{1000mL}{1L}\\\\V=43.46mL$

Best regards!

7 0

2 years ago