Answer:
Cooper and zinc if I remember right
Answer:
Molarity is halved when the volume of solvent is doubled.
Explanation:
Using the dilution equation (volume 1)(molarity 1)=(volume 2)(molarity 2), we can demonstrate the effects of doubling volume.
Suppose the starting volume is 1 L and the starting molarity is 1 M, and doubling the volume would make the final volume 2 L.
Plugging these numbers into the equation, we can figure out the final molarity.
(1 L)(1 M)=(2 L)(X M)
X M= (1 L x 1 M)/(2 L)
X M= 1/2 M
This shows that the molarity is halved when the volume of solvent is doubled.
1. Mg + CuSO4 —> MgSO4 + Cu
=> Single displacement reaction
2. 2HCI + Mg(OH)2 —> MgCI2 + H2O
=> Acid - base reaction
3.AgNO3 + NaCI —> AgCI + NaNO3
=> Double displacement reaction
B is the answer to your question
