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Hitman42 [59]
3 years ago
15

Sodium metal is placed in water to produce sodium hydroxide (NaOH)

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer:

a Sodium

Explanation:

The solid in this reaction is the sodium metal. A solid is a substance held together by attractive forces that are very strong.

Solids have a fixed shape and volume.

  • Metals are solids
  • Sodium is an alkali metal belonging to the first group on the periodic table.
  • This solid combines with the liquid water.
  • The product is an aqueous sodium hydroxide.
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How many moles of Na2SO4, are produced from 7.00 moles of (NH4)2SO4?
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A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
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<h3>25.0 grams is the mass of the steel bar.</h3>

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Heat gained by steel bar will be equal to heat lost by the water

Q_1=-Q_2

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Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))

On substituting all values:

(m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}

<h3>25.0 grams is the mass of the steel bar.</h3>
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Answer:

The gas obeys Boyle’s law and the value of k_i\&k_f both are equal to 40.0 atm L.

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The gas in the cylinder is obeying Boyle's law.

The gas obeys Boyle’s law and the value of k_i\&k_f both are equal to 40.0 atm L.

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