Answer:
F = 1015 N
Explanation:
Given that,
Mass of a ball, m = 0.145 kg
Initial speed, u = 20 m/s
Final speed, v = -15 m/s (as it moves in opposite direction)
The ball and bat were in contact for 5 ms
We need to find the force the bat applies to the bat. We know that,
F = ma
So, the bat will apply 1015 N force to the ball.
Answer:
4 m, 1.71 m and 6.29 m
Explanation:
Let L = 8 m be the distance between the two speakers. Let x be the distance from speaker A of constructive interference. The distance to speaker B from the point of constructive interference is thus x₁ = L - x.
There is constructive interference when the distance x₁ - x = nλ where n = is an integer and λ = wavelength L - x
x₁ - x = nλ
L - x - x = nλ
L - 2x = nλ
x = (L - nλ)/2 = (L - nv/f)/2. where v = speed of wave = 343 m/s and f = frequency = 75 Hz
The distance from A where constructive interference would occur starts from when
n = 0
x₂ = (L - nv/f)/2 = (8 - 0 × 343/75)/2 = (8 - 0)/2 = 8/2 = 4 m
n = 1
x₃ = (L - nv/f)/2 = (8 - 1 × 343/75)/2 = (8 - 4.57)/2 = 3.43/2 = 1.71 m
when n = 2
x₄ = (L - nv/f)/2 = (8 - 2 × 343/75)/2 = (8 - 9.14)/2 = -1.15/2 = -0.57 m
So the value at n = 2 is not included.
The third point occurs at x₅ = L - x₃ where x₃ = 1.71 m is the distance away from point B where constructive interference also occurs. (since it is symmetrical about the point x₂ = 4 m
x₅ = L - x₃ = 8 - 1.71 = 6.29 m
Answer:
You could put sheet metal lining the bottom or something similar to that
Explanation:
I think it's B ,go to physicsclassroom.com Newton's second law
