All categories

3 years ago

Will give

Physics

2 answers:

Nataly [62]3 years ago

6 0

Answer:

True

Explanation:

Leno4ka [110]3 years ago

6 0

Answer:

True.

Explanation:

Hope this helps!!! <3

You might be interested in

A 0.0600-kilogram ball traveling at 60.0 meters per second hits a concrete wall. What speed must a 0.0100-kilogram bullet have i

GarryVolchara [31]

Answer:

the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is 360 m/s

Explanation:

The computation of the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is as follows:

The ball momentum is

$\Delta Q = mv\\\\\Delta Q = 6 \times 1^-2 \times 60\\\\\Delta Q = 3.6 kg \times m/s$

As there is a similar momentum

So,

$\Delta Q = MV\\\\3.6 = 10^-2V\\\\V = 360 m/s$

Hence, the speed that have 0.0100 kilogram bullet with the similar momentum magnitude is 360 m/s

5 0

3 years ago

Help me please (*˘︶˘*).｡*♡

ss7ja [257]

Answer:

your answer is number 4

Explanation:

Hope it helps :)

pls mark brainliets :P

5 0

2 years ago

Read 2 more answers

A truck covers 40.0 m in 7.80 s while uniformly slowing down to a final velocity of 1.70 m/s. Please provide with explanation an

Karolina [17]

Answer:

a = -0.223 m/s

Explanation:

4 0

3 years ago

Una ola oceánica viaja a aproximadamente 1,97 m / s. Esto es 4 millas por hora. La frecuencia de las ondas es de aproximadamente

yKpoI14uk [10]

Answer:

λ = 28,14 m

Explanation:

To find the wavelength of the wave you use the following formula:

$v=\lambda f$ (1)

v: speed of the wave = 1,97 m/s

λ: wavelength

f: frequency of the wave = 0,07 Hz

You replace the values of v and f in the equation (1) and solve for λ:

$\lambda=\frac{v}{f}=\frac{1,97m/s}{0,07Hz}=28,14m$

hence, the wavelength of the wave is 28,14 m

5 0

3 years ago

A golfer hits a ball at an angle of 12 degrees above horizontal. The velocity of the ball is 37 m/s. What is the horizontal dist

ruslelena [56]

72 m is the horizontal distance the travels.

Option: C

Explanation:

The units to express the horizontal and vertical distances are meters (m). The "horizontal" and "vertical" velocities are expressed in "meters per second" (m/s).

Horizontal distance = (initial horizontal velocity)(time)

We can now get the range x from the horizontal component of velocity

$x=v_{x o} \times t$ equation (1)

$\mathrm{v}_{\mathrm{xo}}=\text { initial horizontal velocity }(\mathrm{m} / \mathrm{s})$

x = horizontal distance (m)

t = time (s)

$\mathrm{v}_{\mathrm{x} \mathrm{o}}=\mathrm{v} \cos \theta$

We know that, V = 37 m/s, θ = 12 degree and t = 2 seconds.

To find, $\mathrm{v}_{\mathrm{x} \mathrm{o}}=\mathrm{v} \cos \theta$

$\mathrm{V}_{\mathrm{x} \mathrm{o}}=37 \times \cos 12$

$\mathrm{V}_{\mathrm{x} \mathrm{o}}=37 \times 0.974$

$\mathrm{V}_{\mathrm{x} \mathrm{o}}=36.038$

$\mathrm{Now}, \mathrm{x}=\mathrm{v}_{\mathrm{xot}}$

$x=36.038 \times 2$

x = 72.076 m ~ 72 m

x = 72 m

The horizontal distance is 72 m.

5 0

3 years ago