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Allushta [10]
3 years ago
9

Technician A says that you don’t need to use an exhaust extraction system when working on vehicles equipped with a catalytic con

verter. Technician B says that carbon monoxide effectively asphyxiates a person. Who is correct?
Engineering
1 answer:
pav-90 [236]3 years ago
8 0

Answer:

Technician B

Explanation:

When working on vehicles which are equipped with a catalytic coverter, the best practice of asphyxiating someone is to use carbon monoxide. This implies that you need an extraction sytem. Therefore, technician A is wrong by assuming no need of the system. In conclusion, technician B is correct.

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Depending on the vehicle, there are typically between two and 12 cylinders in its engine, with a piston moving up and down in each.

Explanation:

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When handling chemicals and solvents, technicians are recommended to
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Read 2 more answers
In the circuit given below, R1 = 17 kΩ, R2 = 74 kΩ, and R3 = 5 MΩ. Calculate the gain 1formula58.mml when the switch is in posit
Elenna [48]

Answer:a

a) Vo/Vi = - 3.4

b) Vo/Vi = - 14.8

c) Vo/Vi = - 1000

Explanation:

a)

R1 = 17kΩ

for ideal op-amp

Va≈Vb=0 so Va=0

(Va - Vi)/5kΩ + (Va -Vo)/17kΩ = 0

sin we know Va≈Vb=0

so

-Vi/5kΩ + -Vo/17kΩ = 0

Vo/Vi = - 17k/5k

Vo/Vi = -3.4

║Vo/Vi ║ = 3.4    ( negative sign phase inversion)

b)

R2 = 74kΩ

for ideal op-amp

Va≈Vb=0 so Va=0

so

(Va-Vi)/5kΩ + (Va-Vo)74kΩ = 0

-Vi/5kΩ + -Vo/74kΩ = 0

Vo/Vi = - 74kΩ/5kΩ

Vo/Vi = - 14.8

║Vo/Vi ║ = 14.8  ( negative sign phase inversion)

c)

Also for ideal op-amp

Va≈Vb=0 so Va=0

Now for position 3 we apply nodal analysis we got at position 1

(Va - Vi)/5kΩ + (Va - Vo)/5000kΩ = 0           ( 5MΩ = 5000kΩ )

so

-Vi/5kΩ + -Vo/5000kΩ = 0

Vo/Vi = - 5000kΩ/5kΩ

Vo/Vi = - 1000

║Vo/Vi ║ = 1000  ( negative sign phase inversion)

3 0
3 years ago
Hi, any kind of help on these questions will be appreciated.
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Answer:

IDK

Explanation:

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Each of the following activities are commonly performed during the implementation of the Database Life Cycle (DBLC). Fill in the
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