Answer:
mechanical power used to overcome frictional effects in piping is 2.37 hp
Explanation:
given data
efficient pump = 80%
power input = 20 hp
rate = 1.5 ft³/s
free surface = 80 ft
solution
we use mechanical pumping power delivered to water is
.............1
put here value
= (0.80)(20)
= 16 hp
and
now we get change in the total mechanical energy of water is equal to the change in its potential energy
..............2
and that can be express as
..................3
so
![\Delta {E_{mech}} = (62.4lbm/ft^3)(1.5ft^3/s)(32.2ft/s^2)(80ft)[\frac{1lbf}{32.2lbm\cdot ft/s^2}][\frac{1hp}{550lbf \cdot ft/s}]](https://tex.z-dn.net/?f=%5CDelta%20%7BE_%7Bmech%7D%7D%20%3D%20%2862.4lbm%2Fft%5E3%29%281.5ft%5E3%2Fs%29%2832.2ft%2Fs%5E2%29%2880ft%29%5B%5Cfrac%7B1lbf%7D%7B32.2lbm%5Ccdot%20ft%2Fs%5E2%7D%5D%5B%5Cfrac%7B1hp%7D%7B550lbf%20%5Ccdot%20ft%2Fs%7D%5D)
......4
solve it we get
hp
so here
due to frictional effects, mechanical power lost in piping
we get here
put here value
= 16 -13.614
= 2.37 hp
so mechanical power used to overcome frictional effects in piping is 2.37 hp
Answer:
Both Technician A and B are correct.
Explanation: Both are correct, but keep note that different color coolants leave different color stains.
Answer:
1.0MG
Explanation:
to solve this problem we use this formula
S₀-S/t = ksx --- (1)
the values have been given as
concentration = S₀ = 250mg
effluent concentration = S= 10mg
value of K = 0.04L/day
x = 3000 mg
when we put these values into this equation,
250-10/t = 0.04x10x3000
240/t = 1200
we cross multiply from this stage
240 = 1200t
t = 240/1200
t = 0.2
remember the question says that 5MGD is required to be treated
so the volume would be
v = 0.2x5
= 1.0 MG
D pad or rb or lb hop this helps
