Answer: It helps your back posture and shows respect
Explanation:
Answer:
Q= 6491.100 kJ/s
Explanation:
Air-Fuel Ratio:
For a combustion reaction the proportion of air that is present in a gaseous substance responsible for the reaction,this proportion is known as air-fuel ratio.The air fuel ratio is calculated using the combustion reaction for the substance.
Considering reaction for the Ethanol as
C₂H₅OH +XO₂(O₂+3.76N₂)→ aCO₂+bH₂O+cN₂
Balancing the equation we get;
a=2,
2b=6
∴ b=3
xO₂=3
The air-fuel ratio
A/F = XO₂+H₂O+xN₂× mass of N₂/mass(fuel)
3.31×31.9+11.28×28.013/46.069
= 8.943
Equivalent ratio = 0.7,
so, heat transfer
Q= m ×Cp×ΔT
= 75×0.7×112.4(1500-400)
Q= 6491.100 kJ/s
1kJ/s=1000w
∴ Q= 6491100 W
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Answer: the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr
Explanation:
F, W and B are the fresh feed, brine and total water obtained
w = 2 x 10^4 L/h
we know that
F = W + B
we substitute
F = 2 x 10^4 + B
F = 20000 + B .................EQUA 1
solute
0.035F = 0.05B
B = 0.035F/0.05
B = 0.7F
now we substitute value of B in equation 1
F = 20000 + 0.7F
0.3F = 20000
F = 20000/0.3
F = 66666.67 kg/hr
B = 0.7F
B = 0.7 * F
B = 0.7 * 66666.67
B = 46,666.669 kg/hr
the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr
Answer:
c I think so haven't took engineering in ages
Answer:
The answer is A.) joule
Explanation:
a joule is the heat unit and the watt is the measure of heat transfered.
