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3 years ago

In case of damaged prestressed concrete I girders which are used for restoring strength?

Engineering

1 answer:

Ahat [919]3 years ago

7 0

Answer: The use of post-tensioning rods is useful in this situation.

Explanation:

The prestressed concrete has not been accepted as a good building material. The high tensile strength of steel is combined with the concrete to give the compressive strength to the concrete.

Post-tensioning rods of steel along with jacking can be used to restore the strength of the prestressed girder and it can begin with the calculated preload. This way the damaged concrete can be repaired and restored.

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Tech A says that a faulty vacuum booster can affect engine operation. Tech b says that steal brake Ponce can be replaced with a

GaryK [48]

Answer:

Tech A

Explanation:

A faulty vacuum booster can actually affect the operation of an engine. Engine stalls when brakes are applied. And this can happen when the diaphragm that is inside the brake booster fails. The failing thus allows air to bypass the seal. When the brakes are then pressed, the engine will actually feel like it will stall, and the idle will most probably drop. Also, asides a reduction in the break performance quality, a stalling engine is very bad and can result to many negative effects.

3 0

4 years ago

Convert

Helen [10]

Answer:

(a) $1.308\times 10^{-4}m/sec$

(b)57.33831 pound/cubic feet

Explanation:

We have

(a) 760 miles / hour

We know that $1\ mile\ =0.00062m$

And 1 hour = 60×60=3600 sec

So $760miles/hour=\frac{760\times 0.00062meter}{3600sec}=1.308\times 10^{-4}m/sec$

(b) 927 kg/cubic meter to mass/cubic foot

We know that 1 kg = 2.20 pound

So 921 kg = 921×2.20=2026.2 pound

We know that 1 cubic meter = 35.31 cubic feet

So 57.33831 pound / cubic feet

$5.37\times 10^3kj/min=\frac{5.37\times 1000kj}{60sec}=89.5kj/sec$

We know that 1 kj /sec = 1.341 hp

So 89.5 kj/sec = 89.5××1.341=120.1095 hp

7 0

4 years ago

Consider the following ways of handling deadlock: (1) banker’s algorithm, (2) detect

Andrew [12]

Answer:

Explanation:

7 0

3 years ago

What’s a pigtail when wiring

Levart [38]

Answer:

A pigtail when wiring is technique that is used in connecting a lot of wires together.

Explanation:

A pigtail is a wire that is short in length. It has two ends. One end has a connector while the other end has other wires connected to it.

Pigtail when wiring is the connection of more than one wire in a circuit to another device. Pigtail when wiring helps to extend the length of the wire in a circuit if the wire used it short).

Pigtail when wiring is a technique what helps to keep the circuit organised because it prevents the wires from getting tangled.

7 0

4 years ago

A 0.5 m^3 container is filled with a mixture of 10% by volume ethanol and 90% by volume water at 25 °C. Find the weight of the l

svp [43]

Answer:

total weight of liquid = 4788.25 N or 488.09 kg

Explanation:

given data

total volume = 0.5 m³

volume of ethanol = 10 % of volume = 0.10 × 0.5 = 0.05 m³

volume of water = 90 % at 25 °C of volume = 0.90 × 0.5 = 0.45 m³

to find out

weight of the liquid

solution

we know that density of water at 25 is 997 kg/m³

and density of ethanol is 789 kg/m³

so weight of water is = density × volume × g

put here value and we take g = 9.81

weight of water is = 997 × 0.45 × 9.81

weight of water = 4401.25 N ......................1

weight of ethanol is = density × volume × g

put here value and we take g = 9.81

weight of ethanol is = 789 × 0.05 × 9.81

weight of ethanol = 387.00 N ...............2

so total weight of liquid = sum of equation 1 add 2

total weight of liquid = 4401.25 + 387

total weight of liquid = 4788.25 N or 488.09 kg

7 0

3 years ago