All categories

3 years ago

An ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. The momentum

Physics

1 answer:

dimulka [17.4K]3 years ago

6 0

Answer:

B. Increases

Explanation:

Momentum is given as $p=mv$ . Since $m$ is maintained, as the velocity decreases, the momentum decreases, and similarly, as the velocity increases, the momentum increases.

You might be interested in

In a wheel and axle, the radius of the wheel is 20 cm and the radius of the axle is 4 cm. What is the mechanical advantage?

aliya0001 [1]

The answer is 5. To find the advantage you just divide 20 by 4.

4 0

3 years ago

Read 2 more answers

??? True or false. An element can only exist as an individual atom.

KengaRu [80]

I think it's false because Oxygen is diatomic so it's found as O2 which means that it has two atoms of itself.

7 0

4 years ago

A block rests on a frictionless horizontal surface and is attached to a spring. When set into simple harmonic motion, the block

MariettaO [177]

Answer:

v₀ = 0.5058 m/s

Explanation:

From the question, for the block to hit the bottle, the elastic potential energy of the spring at the bottle (x = 0.08 m) should be equal to the sum of the elastic potential energy of the spring at x = 0.05 m and the kinetic energy of block at x = 0.05 m

Now, the potential energy of the block at x = 0.08 m is ½kx²

where;

k is the spring constant given by; k = ω²m

ω is the angular velocity of the oscillation

m is the mass of the block.

Thus, potential energy of the spring at the bottle(x = 0.08 m) is;

U = ½ω²m(0.08m)²

Also, potential energy of the spring at the bottle(x = 0.05 m) is;

U = ½ω²m(0.05m)²

and the kinetic energy of the block at x = 0.05 m is;

K = ½mv₀²

Thus;

½ω²m(0.08)² = ½ω²m(0.05)² + ½mv₀²

Inspecting this, ½m will cancel out to give;

ω²(0.08)² = ω²(0.05)² + v₀²

Making v₀ the subject, we have;

v₀ = ω√((0.08)² - (0.05)²)

So,

v₀ = 8.1√((0.08)² - (0.05)²)

v₀ = 0.5058 m/s

7 0

3 years ago

(i) What is the acceleration of an object between 0-4 seconds?

DENIUS [597]

Answer:

Your small tiny face

Explanation:

HIHIHIIHHI

4 0

3 years ago

What is the significance of the fact that the gravitational constant, G, is a very small number and that Coulomb’s constant, k,

valina [46]

Both are constants used in the definition of Forces (gravitational and electric,respectively)

Since those constants are proportional to the magnitude of the forces:

Having a small gravitational constant explains why there is no apparent force of attraction with objects of considerable low mass (they would need to have great value of mass for the equation to give an apreciable force)

Electrical interactions are usually strong, and thus require an appropiate constant to depict the phenomenon. We deal in this case with charges really small, but the forces are in different order of magnitude.

5 0

4 years ago

Read 2 more answers