Answer:
The final velocity of the object is 330 m/s.
Explanation:
To solve this problem, we first must find the acceleration of the object. We can do this using Newton's Second Law, given by the following equation:
F = ma
If we plug in the values that we are given in the problem, we get:
42 = 7 (a)
To solve for a, we simply divide both sides of the equation by 7.
42/7 = 7a/7
a = 6 m/s^2
Next, we should write out all of the information we have and what we are looking for.
a = 6 m/s^2
v1 = 0 m/s
t = 55 s
v2 = ?
We can use a kinematic equation to solve this problem. We should use:
v2 = v1 + at
If we plug in the values listed above, we should get:
v2 = 0 + (6)(55)
Next, we should solve the problem by performing the multiplication on the right side of the equation.
v2 = 330 m/s
Therefore, the final velocity reached by the object is 330 m/s.
Hope this helps!
The correct answer for the question that is being presented above is this one:
Phi = BAsin(theta)
<span>1. Phi(i) = BA </span>
<span>2. Phi(f) = 0 </span>
3. EMF = N(phi(i)-phi(f))/deltat
Here are the follow-up questions:
<span>1. What is the total magnitude Phi_initial of the magnetic flux through the coil before it is rotated? </span>
<span>2. What is the magnitude Phi_final of the total magnetic flux through the coil after it is rotated? </span>
<span>3. What is the magnitude of the average emf induced in the coil?</span>
<span>Gravitational force is affected by: a. mass c. distance b. weight d. both a and c
Mass.
</span>When an object is above the Earth's surface it hasgravitational potential<span> energy (GPE). The amount of GPE an object has depends on its mass and its height above the Earth's surface</span><span>
</span>
Answer:
C
Explanation:
Fusion and fission are similar in that they both release large amounts of energy. Nuclear fusion is a process in which two nuclei join to form a larger nucleus. Nuclear fission is a process in which a nucleus splits into two smaller nuclei.
Fungi.
A fungi contains paired statements that can be used to identify organisms.