Answer:
y = 9.64 m
Explanation:
This exercise should be solved using kinematics in one dimension, let's write the equations for the two cases presented
The rock is released
y = y₀ + V₀₁ t₁ - ½ g t₁²
In this case the speed starts is zero
y = y₀ - ½ g t₁²
The rock is thrown up
y = y₀ + v₀² t₂ -½ g t₂²
The height that reaches the floor is zero
y₀ - ½ g t₁² = y₀ + v₀₂ t₂ - ½ g t₂²
We use the initial velocity with the equation
v₂² = v₀₂² - 2 g y
At the point of maximum height v₂ = 0
v₀₂ = √ (2 g 
)
g (-t₁² + t₂²) = 2 √ (2 g ) t₂²
g (- 4.15² + 6.30²) = 2 √ (2 2 g) 6.3
g (22.4675) = 25.2 √ g
g² = 2²5.2 / 22.4675 g
g = 1.12 m / s²
Having the value of g we can use any equation to find the height
y = ½ g t₁²
y = ½ 1.12 4.15²
y = 9.64 m
Answer:
have tried it and the units end up being Nm^-2 (the unit of stress) however the unit for joules is Nm.
Source https://www.physicsforums.com/threads/why-does-1-2-stress-strain-equal-the-energy-stored-per-unit-volume-in-a-wire.565495/
Answer:
a) dh/dt = -44.56*10⁻⁴ cm/s
b) dr/dt = -17.82*10⁻⁴ cm/s
Explanation:
Given:
Q = dV/dt = -35 cm³/s
R = 1.00 m
H = 2.50 m
if h = 125 cm
a) dh/dt = ?
b) dr/dt = ?
We know that
V = π*r²*h/3
and
tan ∅ = H/R = 2.5m / 1m = 2.5 ⇒ h/r = 2.5
⇒ h = (5/2)*r
⇒ r = (2/5)*h
If we apply
Q = dV/dt = -35 = d(π*r²*h/3)*dt
⇒ d(r²*h)/dt = 3*35/π = 105/π ⇒ d(r²*h)/dt = -105/π
a) if r = (2/5)*h
⇒ d(r²*h)/dt = d(((2/5)*h)²*h)/dt = (4/25)*d(h³)/dt = -105/π
⇒ (4/25)(3*h²)(dh/dt) = -105/π
⇒ dh/dt = -875/(4π*h²)
b) if h = (5/2)*r
Q = dV/dt = -35 = d(π*r²*h/3)*dt
⇒ d(r²*h)/dt = d(r²*(5/2)*r)/dt = (5/2)*d(r³)/dt = -105/π
⇒ (5/2)*(3*r²)(dr/dt) = -105/π
⇒ dr/dt = -14/(π*r²)
Now, using h = 125 cm
dh/dt = -875/(4π*h²) = -875/(4π*(125)²)
⇒ dh/dt = -44.56*10⁻⁴ cm/s
then
h = 125 cm ⇒ r = (2/5)*h = (2/5)*(125 cm)
⇒ r = 50 cm
⇒ dr/dt = -14/(π*r²) = - 14/(π*(50)²)
⇒ dr/dt = -17.82*10⁻⁴ cm/s
A lot would happen depends on which perspective you look at it from. Less incoming solar radiation means that there is a greater possibility of the surface temperature of earth reducing. there would be a cooling effect. And it could be major cooling in certain part of the world depending on milankovitch cycles. We know that the amount of light or solar radiation that reaches the earth is unequal in different parts of the world because of the obliquity, eccentricity, and precession of the earth. But, in general you would most likely see a cooling trend around the world and in some parts it would be extreme. In Canada or in the North is general, winters would become even more cooler or colder... winters would become longer perhaps, And summers would 've cooler. on the contrary to what most believe, you would most likely see a decline in precipitation such as snow or rain because this is mostly caused or intensified by warming temperatures. Life would be probably very similar to that of the Pleistocene epoch. how would humans respond to this change... Well most likely they would try to use their tech to control weather because they already do to a smaller proportion.
hope that helps a bit! :)
Answer:
Longitudinal and transverse waves have many similarities and differences.
Explanation:
Similarities:
Mechanical waves can be transverse and longitudinal waves.
Transverse and longitudinal waves both have wavelengths and frequencies.
They both have amplitudes
Both waves can travel through a medium or not, but it depends on whether is an electromagnetic or a mechanical wave.
Differences:
Electromagnetic waves can only be transverse.
The particles of the medium in a longitudinal wave move parallel to the direction (motion) of a wave. It is in this back and forth motion.
The particles of the medium in a transverse wave move perpendicular to the direction (motion) of a wave. This means that there would be right angles showing that they are perpendicular.
Longitudinal waves have rarefactions and compressions.
These rarefactions and compressions are used to measure the wavelength of a wave. For instance, a wavelength in a longitudinal wave is measured from rarefaction to rarefaction
Transverse waves have troughs and crests.
Amplitude in a transverse wave is measured from the midline to the crest of trough.
Amplitude in a longitudinal wave is measured based on how closely packed the particles of the medium are
I hope this helps
