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lapo4ka [179]
3 years ago
5

What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second?

Physics
2 answers:
fiasKO [112]3 years ago
4 0
Momentum = mv
where m is the mass of an electron and v is the velocity of the electron.

v = momentum ÷ m
   = (1.05×10∧-24)÷(9.1×10∧-31) = 1,153,846.154 m/s

kinetic energy = (mv∧2)÷2
                       = (9.1×10∧-31 × 1,153,846.154∧2) ÷2
                      = (1.21154×10∧-18) ÷ 2
                      = 6.05769×10∧-19 J
Tomtit [17]3 years ago
3 0

Answer:

K = 6.02 × 10⁻¹⁹ J

Explanation:

The momentum (p) of an electron is its mass (m) times its speed (v).

p = m × v

v = p / m = (1.05 × 10⁻²⁴ kg.m/s) / 9.11 × 10⁻³¹ kg = 1.15 × 10⁶ m/s

We can find the kinetic energy (K) using the following expression.

K = 1/2 × m × v²

K = 1/2 × 9.11 × 10⁻³¹ kg × (1.15 × 10⁶ m/s)²

K = 6.02 × 10⁻¹⁹ J

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Using the definition of the centripetal force we have:

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<u>Therefore the magnitude of the friction force is 8197.60 N</u>

I hope it helps you!

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The d subshell can hold up to 10 electrons in an atom.<br> true or false
Lady_Fox [76]

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A car with a mass of 1,500 kg is accelerating at a rate of
AURORKA [14]

Answer:

The net force acting on the car is

3

×

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Hope this helps you

Explanation:

Force is defined as the product of the mass of the body and its aaceleration,

⇒

F

=

m

a

Substituting the above given values we get,

F

=

(

1500

k

g

)

(

2.0

m

/

s

2

)

=

3000

N

=

3

×

10

3

N

.

4 0
3 years ago
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