What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second?
2 answers:
Momentum = mv
where m is the mass of an electron and v is the velocity of the electron.
v = momentum ÷ m
= (1.05×10∧-24)÷(9.1×10∧-31) = 1,153,846.154 m/s
kinetic energy = (mv∧2)÷2
= (9.1×10∧-31 × 1,153,846.154∧2) ÷2
= (1.21154×10∧-18) ÷ 2
= 6.05769×10∧-19 J
Answer:
K = 6.02 × 10⁻¹⁹ J
Explanation:
The momentum (p) of an electron is its mass (m) times its speed (v).
p = m × v
v = p / m = (1.05 × 10⁻²⁴ kg.m/s) / 9.11 × 10⁻³¹ kg = 1.15 × 10⁶ m/s
We can find the kinetic energy (K) using the following expression.
K = 1/2 × m × v²
K = 1/2 × 9.11 × 10⁻³¹ kg × (1.15 × 10⁶ m/s)²
K = 6.02 × 10⁻¹⁹ J
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