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3 years ago

What distinguishes a nebula and a star?

1 answer:

4 0

What distinguishes a nebula and a star is that a nebula is a cloud of gas and dust in outer space, visible in the night sky either as an indistinct bright patch or as a dark silhouette against other luminous matter. And a star is a<span> type of astronomical object consisting of a luminous spheroid of plasma held together by its own gravity.</span>

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Find the current flowing out of the battery.

klemol [59]

Answer:

0.36 A.

Explanation:

We'll begin by calculating the equivalent resistance between 35 Ω and 20 Ω resistor. This is illustrated below:

Resistor 1 (R₁) = 35 Ω

Resistor 2 (R₂) = 20 Ω

Equivalent Resistance (Rₑq) =?

Since, the two resistors are in parallel connections, their equivalence can be obtained as follow:

Rₑq = (R₁ × R₂) / (R₁ + R₂)

Rₑq = (35 × 20) / (35 + 20)

Rₑq = 700 / 55

Rₑq = 12.73 Ω

Next, we shall determine the total resistance in the circuit. This can be obtained as follow:

Equivalent resistance between 35 Ω and 20 Ω (Rₑq) = 12.73 Ω

Resistor 3 (R₃) = 15 Ω

Total resistance (R) in the circuit =?

R = Rₑq + R₃ (they are in series connection)

R = 12.73 + 15

R = 27.73 Ω

Finally, we shall determine the current. This can be obtained as follow:

Total resistance (R) = 27.73 Ω

Voltage (V) = 10 V

Current (I) =?

V = IR

10 = I × 27.73

Divide both side by 27.73

I = 10 / 27.73

I = 0.36 A

Therefore, the current is 0.36 A.

6 0

3 years ago

What kind of device can you use to to separate visible light into its different colors

juin [17]

A prism will separate white light into a rainbow of light

5 0

3 years ago

An Earth satellite is orbiting at a distance from the Earth's surface equal to one Earth radius (4 000 miles). At this location,

Taya2010 [7]

Answer:0.25 times

Explanation:

Given

Distance of satellite from earth surface=Radius of earth

Force on the satellite is F=mg'

where g'=acceleration due to gravity at that point

Distance from center of Earth=R+R=2R

Gravitational Force is given by

$F=\frac{GM_1M_2}{r^2}$

Force $F=mg'=\frac{GMm}{4R^2}-----1$

Force on earth surface $F=mg=\frac{GMm}{R^2}------2$

Divide 1 and 2 we get

$\frac{g'}{g}=\frac{R^2}{4R^2}$

$g'=\frac{g}{4}$

7 0

3 years ago

When do vernal equinoxes usually occur? autumnal?

shepuryov [24]

Spring tides occur twice each lunar month all year long without regard to the season. Neap tides, which also occur twice a month, happen when the sun and moon are at right angles to each other. ... The moon appears full when the Earth is between the moon and the sun

7 0

3 years ago

A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. C

lozanna [386]

Hello!

A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. Calculate the average speed.

We have the following data:

* velocity (in mph)

(V1) = 35.0 mph

(V2) = 40.0 mph

(V3) = 50.0 mph

* weights for the time (in hours)

(T1) = 1.00 hour

(T2) = 0.0500 hour

(T3) = 2.00 hours

We apply the data to the weighted average formula to find the average speed, let us see:

$Weight\:Average = \dfrac{V_1*T_1+V_2*T_2+V_3*T_3}{T_1+T_2+T_3}$