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3 years ago

Can anybody help?? If somebody can answer I'd love it!!

Physics

1 answer:

Bas_tet [7]3 years ago

8 0

Answer:

a. T

b. F

c. T

d. F

e. T

2. Liquid, gas, solid

3. Water

a. Solid

b. Gas

c. Water

a. Add heat

b. Remove heat

c. Add heat

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A(n) 0.2 kg object is swung in a vertical circular path on a string 0.1 m long. The acceleration of gravity is 9.8 m/s2 . If a c

Leya [2.2K]

Answer:

$T=83.37N$

Explanation:

Since the object is under a circular motion, according to Newton's second law, when the object is at the top of the circle we have:

$\sum F_y: T-mg=F_c$

Where $F_c$ is the centripetal force and is given by:

$F_c=ma_c=m\frac{v^2}{r}$

Replacing and solving for T:

$T=m\frac{v^2}{r}+mg\\T=0.2kg\frac{(6.38\frac{m}{s})^2}{0.1m}+0.2kg(9.8\frac{m}{s^2})\\T=83.37N$

8 0

3 years ago

011 10.0 points

Sedbober [7]

<h2>The temperature of the air is 66.8° C</h2>

Explanation:

From the Newton's velocity of sound relationship , the velocity of sound is directly proportional to the square root of temperature .

In this case The velocity of sound = frequency x wavelength

= 798 x 0.48 = 383 m/sec

Suppose the temperature at this time = T K

Thus 383 ∝ $\sqrt{T}$ I

The velocity of sound is 329 m/s at 273 K ( given )

Thus 329 ∝ $\sqrt{273}$ II

Dividing I by II , we have

$\frac{383}{329}$ = $\sqrt{\frac{T}{273} }$

or $\frac{T}{273}$ = 1.25

and T = 339.8 K = 66.8° C

4 0

3 years ago

what is the displacement of the earth after one orbit about the the sun? what is the average velocity of the earth after one orb

valina [46]

5.7 seconds idk idk

6 0

3 years ago

2. Suppose your car has a maximum braking acceleration of -5 m/s2. Calculate the stopping distance for an initial speed of 25 m/

Hitman42 [59]

Answer:

s=62.5m

Explanation:

Use the equation v²=u²+2as, where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance.

0²=25²+2(-5)s

10s=625

s=62.5m

3 0

2 years ago

A 23.7 kg kid slides down a

anyanavicka [17]

Answer:

$\text { The acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}$

Explanation:

Mass of the kid 23.7 kg.

$\text { The kid is accelerating down at an angle is } 47.2^{\circ} .$

$^{\prime \prime} \mathrm{g}^{\prime \prime} \text { acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}$

We need to find the acceleration of the kid,

We know that, Parallel force acted on the kid at an angle is

F = m × g × sinθ (F = ma)

m × a = m × g × sinθ

Now, substitute the given values in the above formula to find acceleration of the kid,

$23.7 \times a=23.7 \times 9.8 \times \sin 47.2^{\circ}$

23.7 × a = 232.26 × 0.733

23.7 × a = 170.24

$a=\frac{170.24}{23.7}$

$a=7.18 \mathrm{m} / \mathrm{s}^{2}$

$\text { Therefore, acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}$

6 0

2 years ago